Geometry Homework Practice Workbook 1st Edition Chapter 1 Points Lines and Planes
Geometry Homework Practice Workbook 1st Edition Chapter 1 Exercise 1.4 Solution Page 7 Problem 1 Answer
The figure is given as
We can clarify that the verte x2 denotes an angle.
The angle can be identified as the vertex denotes the middle of the respective angle.
The angle for the following figure can be named as∠2=∠TVW with vertex as V.
Read and Learn More Geometry, Homework Practice Workbook 1st Edition Solutions
The angle for the following figure can be named as∠2=∠TVW with vertex as V.
Page 7 Problem 2 Answer
The figure is given as
We can clarify that the vertex 5 denotes an angle.
The angle can be identified as the vertex denotes the middle of the respective angle.
The angle for the following figure can be named as ∠5=∠STW with vertex as T.
The angle for the following figure can be named as ∠5=∠STW with vertex as T.
Solutions For Points, Lines, And Planes Exercise 1.4 Page 7 Problem 3 Answer
Page 7 Problem 4 Answer
The figure is given as
We can clarify that the angle ∠STV is defined in the figure.
The side can be identified as each set of adjacent points creates an edge or side.
In the following figure,∠STV is defined by three points S,T,V.
Hence the defined sides are ST and TV.
The defined side of the following angles are ST and TV.
Geometry Homework Practice Workbook Chapter 1 Page 7 Problem 5 Answer
The figure is given as
We can clarify that the verte x4 denotes an angle.
The angle can be identified as the vertex denotes the middle of the respective angle.
The angle for the following figure can be named as ∠4=∠UTS.
The angle for the following figure can be named as∠UTS.
Geometry Workbook 1st Edition Exercise 1.4 Solutions Page 7 Problem 6 Answer
The figure is given as
We can clarify that the angle ∠WTS denotes a defined angle.
The angle can be identified as the vertex denotes the middle of the respective angle.
The angle for the following figure can be named as∠WTS=∠5 with vertex as
The angle for the following figure can be named as∠TSW=∠5 with vertex as T.
Points, Lines, And Planes Solutions Chapter 1 Exercise 1.4 Geometry Workbook Page 7 Problem 7 Answer
Given the figure that is
Here the angle∠2 is located at the point V inside the triangle ΔTWV.So the name of that angle is∠WVT.
Hence, another name of∠2 is∠WVT.
Step-By-Step Solutions For Geometry Homework Practice Workbook Chapter 1 Exercise 1.4 Page 7 Problem 8 Answer
The given figure is,
Here the angle∠OMN is said to be an acute angle because the line OM is not perpendicular to the baseline and it makes the angle in such a way that it does not exceed 90∘.
So, now by using a protractor we can say the measurement of this angle is 40∘.
Therefore, the measurement of the angle is 40∘and so it is an acute angle.
Geometry Homework Practice Workbook Chapter 1 Page 7 Problem 9 Answer
The given figure is,
Here the angle∠QMN is said to be an obtuse angle because the line QM is not perpendicular to the baseline and it makes the angle in such a way that it exceeds 90∘.
So, now by using a protractor we can say the measurement of this angle is 140∘.
Therefore, the measurement of the angle is 140∘and so it is an obtuse angle.
Geometry Chapter 1 Exercise 1.4 Free Solutions Page 7 Problem 10 Answer
Given the figure is,
Here the angle∠QMO is an obtuse angle because no line making this angle is perpendicular to each other.
Using a protractor the angle is found out as 100∘ .
Therefore, the measurement of the angle is 100∘and so it is an obtuse angle.
Geometry Homework Practice Workbook Chapter 1 Page 7 Problem 11 Answer
Given the figure is,
Here BD bisects the angle∠EBC
so∠EBD is half of∠EBC.
Putting the value of both angles and solving both sides we will get the value of x.
Let’s put the value of x and get∠EBC.
Given that∠EBD=4x−8 and∠EBC=5x+20
From the given figure we can say∠EBD=1/2∠EBC.
So by replacing the value of∠EBD&∠EBC in the above formula we can say 4x−8=1/2(5x+20) or,
2(4x−8)=5x+20 or,
8x−16=5x+20 or,
8x−5x=20+16 or,
3x=36 or,
x=36/3=12.
Now put the value of x in∠EBC=5x+20
we will get ∠EBC=5×12+20=80.
Therefore, the value of∠EBC is 80∘.
Geometry Homework Practice Workbook Exercise 1.4 Student Solutions Page 8 Problem 12 Answer
Given the figure is,
Here BD⃗bisects the angle∠EBC
so∠EBD is half of∠EBC.
Putting the value of both angles and solving both sides we will get the value ofx.
Let’s put the value of x and get∠EBC.
Given that∠EBD=4x−8 and∠EBC=5x+20
From the given figure we can say∠EBD=1/2∠EBC.
So by replacing the value of∠EBD&∠EBC in the above formula we can say
4x−8=1/2(5x+20)or,
2(4x−8)=5x+20or,
8x−16=5x+20or,
8x−5x=20+16or,
3x=36or,
x=36/3=12.
Now put the value of x in∠EBC=5x+20
we will get ∠EBC=5×12+20 =80.
Therefore, the value of∠EBC is 80∘.
Points, Lines, And Planes Exercise 1.4 Geometry Workbook Answers Page 8 Problem 13 Answer
Given that
Here we have to find the vertex of∠8.
As we know The vertex of an angle is the point where two rays or edges begin or meet so∠8 is∠MOP in the triangle Δ MOP and two edges are MO&OP.
So the common point of two edges is O that is the vertex of∠8.
Hence, the vertex of the angle∠8 is O.
Geometry Homework Practice Workbook Chapter 1 Page 8 Problem 14 Answer
Given,
To find the sides of the angle∠6.
In Euclidean geometry, an angle is the figure formed by two rays, referred to as the sides of the angle.
The sides that form the angle∠6 are NM&NR.
The sides that form the angle∠6 are NM&NR.
Page 8 Problem 15 Answer
Given,
To find the sides of the angle∠2.
In Euclidean geometry, an angle is the figure formed by two rays, referred to as the sides of the angle.
The sides that form the angle∠2 are PM&PR.
The sides that form the angle∠2 are PM&PR.
Geometry Homework Practice Workbook Chapter 1 Page 8 Problem 16 Answer
Given,
To find the sides of the angle∠MOP.
In Euclidean geometry, an angle is the figure formed by two rays, referred to as the sides of the angle.
The sides that form the angle∠MOP are OM&OP.
Hence we can conclude that the sides that form the angle∠MOP Are OM&OP.
Page 8 Problem 17 Answer
Given,
To find the sides of the angle∠OMN.
In Euclidean geometry, an angle is the figure formed by two rays, referred to as the sides of the angle.
The sides that form the angle∠OMN Are MO&MN.
Hence we can conclude that the sides that form the angle∠OMN Are MO&MN.
Geometry Homework Practice Workbook Chapter 1 Page 8 Problem 18 Answer
Given
To determine∠TZW is acute or obtuse or right-angled.
An angle is acute if it is less than 90∘.
An angle is obtuse if it is more than 90∘.
An angle is right if it is equal to 90∘.
To measure the angle of∠TZW place the protractor along any line.
ZW makes an angle of 110∘with respect to ZT.
Hence the required measure of the angle110∘.
Hence we can conclude that∠TZW is an obtuse angle with a measure of 110∘.
Geometry Homework Practice Workbook Chapter 1 Page 8 Problem 19 Answer
Given
To determine∠UZT is acute or obtuse or right-angled.
An angle is acute if it is less than 90∘.
An angle is obtuse if it is more than 90∘.
An angle is right if it is equal to 90∘.
To measure the angle of∠UZT place the protractor along any line.
ZU makes an angle of 20∘with respect to ZT.
Hence we can conclude that∠UZT is an obtuse angle with a measure of 20∘.
Geometry Homework Practice Workbook Chapter 1 Page 8 Problem 20 Answer
Given
In the figure,CD&CB are opposite rays, CE bisects angle∠DCF and CG bisects angle∠FCB.
m∠FCG=9x+3,m∠GCB=13x−9.
To find∠GCB.
CG bisects angle∠FCB thus∠FCG=∠GCB.
Equate the above values and find the value of x.
Equating∠FCG=∠GCB
We get,
9x+3=13x−9
⇒4x=12
⇒x=12/4
⇒x=3.
Therefore,∠GCB=13x−9
=13×3−9
=39−9
=30.
Hence we can conclude that the measure of angle∠GCB=30∘.
Geometry Homework Practice Workbook Chapter 1 Page 8 Problem 21 Answer
Given
To measure and classify the angles∠1&∠2.
By measuring with a protractor the angle∠1=90∘and∠2=120∘.
Since∠1 is less than 90∘
it is an acute angle. Since∠2 is more than 90∘it is an obtuse angle.
Hence we can conclude that∠1=90∘and∠2=120∘and they are acute angle and obtuse angle respectively.