Glencoe Math Course 2 Volume 1 Common Core Student Edition Chapter 4 Rational Numbers Exercise 4.1

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Rational Numbers

 

Glencoe Math Course 2 Volume 1 Chapter 4 Exercise 4.1 Solutions Page 264 Exercise 1 Problem 1

Given:

\(\frac{3}{10}\)

To find –  Write each fraction or mixed number as a decimal.

We know that

\(\frac{3}{10}\)

Use place value to write the equivalent decimal.

\(\frac{3}{10}\) = 0.3

So,\(\frac{3}{10}\) = 0.3

As a decimal, Each fraction or mixed number is \(\frac{3}{10}\) = 0.3 

Read and Learn More Glencoe Math Course 2 Volume 1 Common Core Student Edition Solutions

Given:

\(\frac{3}{25}\)

To find-  Write each fraction or mixed number as a decimal.

We know that

\(\frac{3}{25}\)

Use place value to write the equivalent decimal.

\(\frac{3}{25}\)\(=\frac{3 \times 4}{25 \times 4}\)

⇒  \(\frac{12}{100}\)

⇒  0.12

So, \(\frac{3}{25}\) = 0.12

As a decimal, Each fraction or mixed number is  \(\frac{3}{25}\) = 0.12

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Rational Numbers

Given:

− 6\(\frac{1}{2}\)

To find- Write each fraction or mixed number as a decimal.

We know that

−6\(\frac{1}{2}\)

−6\(\frac{1}{2}\) = −6+ \(\frac{1}{2}\)

⇒ −6 + 0.5

⇒ −5.5

So, -6\(\frac{1}{2}\) =−5.5

As a decimal, Each fraction or mixed number is −6\(\frac{1}{2}\) =−5.5

 

Given:

−\(\frac{7}{8}\)

To find- Write each fraction or mixed number as a decimal.

We know that −\(\frac{7}{8}\)

Then using long division for 7 divided by 8 and rounding Decimal Places gives us −1.142

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Rational Numbers

Given:

2\(\frac{1}{8}\)

To find- Write each fraction or mixed number as a decimal.

We know that

2\(\frac{1}{8}\)

= 2 + \(\frac{1}{8}\)

= 2 +0.125

= 2.125

2\(\frac{1}{8}\) = 2.125

Then using long division for  2\(\frac{1}{8}\) and rounding Decimal Places gives us 2.125

 

Given:

− \(\frac{3}{11}\)

To find- Write each fraction or mixed number as a decimal.

We know that

−\(\frac{3}{11}\)

 

So, −\(\frac{3}{11}\) = 0.273

Then using long division for –\(\frac{3}{11}\) and rounding Decimal Places gives us 0.273.

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Rational Numbers

Given:

8\(\frac{1}{3}\)

To find- Write each fraction or mixed number as a decimal.

We know that

8\(\frac{1}{3}\)

=  8 + \(\frac{1}{3}\)

= 8 + 0.333 = 8.333

8\(\frac{1}{3}\) = 8.333

Then using long division for  8\(\frac{1}{3}\) and rounding Decimal Places gives us 8.333

 

Given: Molly 0.2.

To find-  Write in simplest form

We know that

0.2

0.2 = \(\frac{2}{10}\)

= \(\frac{2}{10}\)

= \(\frac{1}{5}\)

So, \(\frac{1}{5}\) of the fish are Molly

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Rational Numbers

Given: Guppy 0.25

To find-  Write in simplest form

We know that

0.25

0.25 = \(\frac{25}{100}\)

= \(\frac{1}{4}\)

So , \(\frac{1}{4}\) of the fish are Guppy

 

Given:

Divide 0.4 by 10 as it is in tenth place, then write in simplest form.

We know that

0.4

0.4 = \(\frac{4}{10}\)

= \(\frac{2}{5}\)

The fraction of the aquarium made up by Angelfish is \(\frac{2}{5}\)

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 266  Exercise 1   Problem 2

Given: \(\frac{2}{5}\)

To find- Write each fraction or mixed number as a decimal.

We know that

\(\frac{2}{5}\)

Then using long division for \(\frac{2}{5}\) and rounding Decimal Places gives us 0.4.

 

Step-By-Step Guide For Exercise 4.1 Chapter 4 Rational Numbers In Glencoe Math Course 2 Page 266  Exercise 2  Problem 3

Given: − \(\frac{9}{10}\)

To find:- Write each fraction or mixed number as a decimal.

We know that

−\(\frac{9}{10}\)

Then using long division for −\(\frac{9}{10}\) and rounding Decimal Places gives us −0.9.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 266  Exercise 3  Problem 4

Given:

\(\frac{5}{9}\)

To find –  Write each fraction or mixed number as a decimal.

We know that

\(\frac{5}{9}\)

Then using long division for \(\frac{5}{9}\)  and rounding Decimal Places gives us 0.556.

 

Exercise 4.1 Solutions For Chapter 4 Rational Numbers Glencoe Math Course 2 Volume 1 Page 266  Exercise 4  Problem  5

Given: During a hockey game, an ice resurfacer travels 0.75 miles.

To find – The fraction which represents this distance.

We know that

0.75

​0.75=\(\frac{75}{100}\)

So, 0.75 = \(\frac{3}{4}\)

Finally, we concluded  0.75 = \(\frac{3}{4}\) fraction represents this distance.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 1  Problem 6

Given: \(\frac{1}{2}\)

To find- Write each fraction or mixed number as a decimal.

We know that

So, \(\frac{1}{2}\) = 0.5

Then using long division for 1 divided by 2 and rounding Decimal Places gives us 0.5

 

Examples of problems from Exercise 4.1 Chapter 4 Rational Numbers in Glencoe Math Course 2 Page 267  Exercise 2  Problem 7

Given: − 4\(\frac{4}{25}\)=

​To find- Write each fraction or mixed number as a decimal.

We know that

−4\(\frac{4}{25}\)

−4\(\frac{4}{25}\) = −4+\(\frac{4}{25}\)

= −4 + 0.16

= − 4.16

So, −4\(\frac{4}{25}\) = − 4.16

Because we know that 25 equals 100 (think quarters to a dollar), converting this fraction to a decimal in the hundredth place will be simple. 4 Times 25 is multiplied by 100 (again, 4 quarters make a dollar).

This means we’d have to multiply 4 by 4 to get \(\frac{16}{100}\)

The decimal for \(\frac{16}{100}\) is 0.16 As a result, 4 equals  \(\frac{4}{25}\) − 4.16

Finally, The decimal for  \(\frac{16}{100}\)  As a result, 4 and equals −4.16.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 3  Problem 8

Given: \(\frac{1}{8}\)

To find- Write each fraction or mixed number as a decimal.

We know that

\(\frac{1}{8}\)

Then using long division for 1 divided by 8 and rounding Decimal Places gives us 0.125.

 

Common Core Exercise 4.1 Chapter 4 Rational Numbers detailed solutions Glencoe Math Course 2 Page 267  Exercise 4  Problem 9

Given:  \(\frac{3}{16}\)

To find- Write each fraction or mixed number as a decimal.

We know that

\(\frac{3}{16}\)

Then using long division for 3 divided by 16 and rounding Decimal Places gives us 0.188

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 5  Problem 10

Given: −\(\frac{33}{50}\)

To find-  Write each fraction or mixed number as a decimal.

We know that –\(\frac{33}{50}\)

Then using long division for −\(\frac{33}{50}\) and rounding Decimal Places gives us−0.66.

 

Student Edition Glencoe Math Course 2 Chapter 4 Rational Numbers Exercise 4.1 solutions guide Page 267  Exercise 6  Problem 11

Given: − \(\frac{17}{40}\)

To find- Write each fraction or mixed number as a decimal.

We know that −\(\frac{17}{40}\)

Then using long division for − \(\frac{17}{40}\) and rounding Decimal Places gives us 0.425

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 7  Problem 12

Given:  5\(\frac{7}{8}\)

To find- Write each fraction or mixed number as a decimal.

We know that

5\(\frac{7}{8}\)

Multiply the denominator by the whole number 8 × 5 = 40

Add the answer to the numerator 5\(\frac{7}{8}\)

40 + 7 = 47

\(\frac{47}{8}\)

Simplified solution

\(=\frac{8 \times 5+7}{8}\)= \(\frac{47}{8}\)

= 5.875

So,5\(\frac{7}{8}\)= 5.875

Then using long division for  5\(\frac{7}{8}\)  and rounding Decimal Places gives us 5.875.

 

Step-by-step answers for Exercise 4.1 Chapter 4 Rational Numbers in Glencoe Math Course 2 Volume 1 Page 267  Exercise 8  Problem 13

Given:  9\(\frac{3}{8}\)

To find- Write each fraction or mixed number as a decimal.

We know that

9\(\frac{3}{8}\)

9\(\frac{3}{8}\) = 9 + \(\frac{3}{8}\)

=  9.375

So, 9\(\frac{3}{8}\) = 9.37

Then using long division for  9\(\frac{3}{8}\) and rounding Decimal Places gives us 9.37.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267   Exercise 9  Problem 14

Given: −\(\frac{8}{9}\)

We know that

Then using long division for −\(\frac{8}{9}\) and rounding Decimal Places gives us−0.89.

 

Page 267   Exercise 10  Problem 15

Given:  − \(\frac{1}{6}\)

To find – Using long division write each fraction or mixed number as a decimal.

Given

−\(\frac{1}{6}\)

The decimal form of −\(\frac{1}{6}\) = − 0.1666

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 11 Problem 16

Given: −\(\frac{8}{11}\)

To find- Write each fraction or mixed number as a decimal.

We know that

\(\frac{8}{11}\)

Then using long division for −\(\frac{8}{11}\)and rounding Decimal Places gives us −0.72.

 

Page 267  Exercise 12  Problem 17

Given:  2\(\frac{6}{11}\)

To find – Write each fraction or mixed number as a decimal.

We know that

2\(\frac{6}{11}\)

2\(\frac{6}{11}\) = 2 +  \(\frac{6}{11}\)

=  2 + 0.5454

=  2.5454

So, 2\(\frac{6}{11}\) = 2.545

Then using long division for  2\(\frac{6}{11}\)  and rounding Decimal Places gives us 2.545.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 13  Problem 18

Given:−0.2

To find- Write each decimal as a fraction or mixed number in simplest form.

We know that

−0.2

Remove the negative sign from the positive decimal value, convert it to a positive fraction, and then apply the negative sign to the fraction response.

Rewrite the decimal number as a fraction with 1  in the denominator

0.2 = \(\frac{0.2}{1}\)

Multiply to remove 1 decimal place. Here, you multiply top and bottom by 10¹ = 10

\(\frac{0.2}{1}\) × \(\frac{10}{10}\)

=  \(\frac{2}{10}\)

Find the Greatest Common Factor (GCF) of 2 and 10, if it exists, and reduce the fraction by dividing both the numerator and denominator by GCF = 2

Here, we concluded the mixed fraction in simplest form is −0.2 = − \(\frac{1}{5}\)

 

Page 267  Exercise 14  Problem 19

Given: 0.55

To find- Write each decimal as a fraction or mixed number in simplest form.

We know that0.55 Rewrite the decimal number as a fraction within the denominator

0.55  = \(\frac{0.55}{1}\)

Multiply to remove 2 decimal places. Here, you multiply the top and bottom by 10²

= 1000\(\frac{0.55}{1}\)× \(\frac{100}{100}\) =  \(\frac{55}{100}\)

Find the Greatest Common Factor (GCF) of 55 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 5

Here, we concluded the mixed fraction in simplest form is 0.55 =\(\frac{11}{20}\)

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 267  Exercise 15  Problem 20

Given: 5.96

To find- Write each decimal as a fraction or mixed number in simplest form.

We know that

5.96

Rewrite the decimal number as a fraction with 1 in the denominator

5.96 = \(\frac{5.96}{1}\)

Multiply to remove 2 decimal places. Here, you multiply top and bottom by 10² = 100\(\frac{5.96}{1}\)×\(\frac{100}{100}\)=\(\frac{596}{100}\)

Find the Greatest Common Factor (GCF) of 596 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 4

Here, we concluded the mixed fraction in simplest form is 5.96 = 5\(\frac{24}{25}\)

 

Page 267   Exercise 17   Problem 21

Given: A Praying mantis is an interesting insect that can rotate its head 180 degrees.

Suppose the praying mantis at the right is 10.5 centimeters long.

To find- The mixed number that represents this length.

We know that

Now think about the length you’ve been given 10.5

10.5 = 10 + 0.5

Because 10 is an integer, all we have to do now is convert 0.5 to fractional form to get a mixed number.

0.5 = \(\frac{5}{10}\)=\(\frac{1}{2}\)

Thus, the number is

10 + 0.5 = 10 + \(\frac{1}{2}\)

⇒ 10 \(\frac{1}{2}\)

As a result, the needed mixed number is 10\(\frac{1}{2}\).

Finally,  10\(\frac{1}{2}\)mixed number represents this length.

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 268  Exercise 18  Problem 22

Given: Suppose you buy a 1.25− pound package of ham at $5.20 per pound. Find the fraction of the pound bought that is find the portion purchased

\(\frac{\text { Number of pounds}}{\text {1 pound }}\)

⇒ \(\frac{1.25}{1}\)

⇒ \(\frac{125}{100}\)

⇒ \(\frac{5}{4}\)

Finally, \(\frac{5}{4}\) fraction of a pound did you buy.

 

Given: Suppose you buy a 1.25− pound package of ham at $5.20 per pound.

To find – How much money did you spend?

We know that

The amount of ham purchased in pounds = 1.25

We have a Ham of 1 pound = ​​$​​5.20

The amount spent on ham = The fraction of a pound bought × Price per pound
​
⇒   \(\frac{5}{4}\) × 5.20

⇒  5 × 1.3

⇒   ​​$​​6.5.

​Finally, ​​$​​6.5 amount is spend on ham.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 268  Exercise 19  Problem 23

Given: Write a fraction that is equivalent to a terminating decimal between 0.5and0.75.

To find-  Write a fraction

We have Because both 0.5 and 0.75 are at two places after decimals, we know they are terminating.

Finding the average of a number that is between these two can be done by adding it and then dividing by two.

Adding both value =0.5 + 0.75 = 1.25

When you divide it by two, you get = 1.25  by 2 = 0.625

When we convert it to a fraction, we obtain

​⇒ \(\frac{0.625}{1}\)

​⇒ \(\frac{625}{1000}\)

​⇒ \(\frac{5}{8}\)

Finally, \(\frac{5}{8}\) is the terminating decimal.

 

Page 268  Exercise 20  Problem 24

Given Fractions in the simplest form that have denominators of2,4,8,16 and 32produce terminating decimals.

Fractions with denominators of  6,12,18, and 24 produce repeating decimals.

To find – The causes of difference.

As you can see, the denominator in  2,4,8,16,32  is of the kind  2¹,2²,2³,2⁴,2⁵.  As a result, the decimal comes to an end.

Consider fractions with denominators of 6,12,18,24.

Now, among all of these
​
6 = 2.3

12 = 2.2.3

18 = 2.3.3

24 = 2.2.2.3
​
All of these integers’ prime factors include a factor other than 2, namely 3.

As previously stated, if the denominator is not in the form of  2^m or 5ⁿ or 2^m⋅5 the decimal is non-terminating.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 268  Exercise 21  Problem 25

Given The value of pi (π)  is 3.1415926…. The mathematician Archimedes believed that π was between 3 \(\frac{1}{7}\) and 3\(\frac{10}{71}\)

Convert the mixed fraction to improper fraction and solve further

Then check whether Archimedes is correct

We know that

π = 3.1415927

3 \(\frac{1}{7}\)

3 \(\frac{1}{7}\) = 3 + \(\frac{1}{7}\)

We know that

\(\frac{1}{7}\)

Is the same as 1 ÷ 7

Therefore, 3\(\frac{1}{7}\) = 3 + (1÷7)

3 + 0.143 = 3.143

3 \(\frac{10}{71}\)= 3 + \(\frac{10}{71}\)

We know that\(\frac{10}{71}\) Is the same as 10 ÷ 71

Then

3 + \(\frac{10}{71}\)= 3+(10÷71)

3 + 0.141 = 3.141

π = 3.1415927

π value has been rounded to seven decimal digits.

3\(\frac{1}{7}\)  = 3.1428571

Compare these numbers to ensure that pi is contained within the mixed fractions.

3\(\frac{10}{71}\) = 3.1408451

= 3.1408451

It is in this instance.

Finally, we concluded the Archimedes’ statement is correct.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 268  Exercise 22  Problem 26

Given:

Tanya drew a model for the fraction\(\frac{4}{6}\)

Which of the following decimals is equal to \(\frac{4}{6}\)

​A. 0.666

B. 0.6

C. 0.667

D. 0.66777

To find – The decimals.

\(\frac{4}{6}\) = 0.666

Finally, we can conclude that the answer is options A and B.

 

Page 269   Exercise 23  Problem 27

Given:  \(\frac{4}{5}\)

To find-  Write each decimal as a fraction or mixed number in simplest form.

We know that

We have the equation  4÷5 = 0.80

Then using long division for 4 divided by 5 and rounding Decimal Places gives us 0.80.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 269  Exercise 25  Problem 28

Given: − \(\frac{4}{9}\)

To find− Using long division write each fraction or mixed number as a decimal.

We know that

The decimal form of  − \(\frac{4}{9}\) is − 0.4444

 

Page 269  Exercise 26   Problem 29

Given:  5\(\frac{1}{3}\)

To find –  Write each decimal as a fraction or mixed number in simplest form.

We know that

Multiply the denominator by the whole number 3 × 5 = 15

Add the answer to the numerator 15 + 1 = 16

Write the answer over the denominator  = \(\frac{16}{3}\)

Simplified Solution

⇒  \(\frac{3×5+1}{3}\) = \(\frac{16}{3}\)

⇒   5.33

Then using long division for   5\(\frac{1}{3}\) rounding Decimal Places gives us 5.33.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 269  Exercise 27  Problem 30

Given: The fraction of a dime that is made up of copper is \(\frac{12}{16}\)

To find- Write this fraction as a decimal

We know that

We have the equation 16 ÷ 12 = 0.750

Then using long division for  \(\frac{12}{16}\)  ,rounding Decimal Places gives us 0.750.

 

Page 269  Exercise 28  Problem 31

Given:

−0.9

To find- Decimal to a fraction or mixed fraction

Here −0.9

Rewrite the decimal number as a fraction with1 in the denominator

0.9  =  \(\frac{0.9}{1}\)

Multiply to remove 1 decimal place. Here, you multiply top and bottom by 10¹ = 10

\(\frac{0.9}{1}\)×\(\frac{10}{10}\) = \(\frac{9}{10}\)

⇒ −0.9 = −\(\frac{9}{10}\)

Finally, we concluded the value in decimal to fraction −0.9  = −\(\frac{9}{10}\)

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 269  Exercise 29  Problem 32

Given:

0.34

To find- Decimal to a fraction or mixed fraction

​Here it is given that  0.34

Rewrite the decimal number as a fraction with 1 in the denominator

0.34 = \(\frac{0.34}{1}\)

Multiply to remove 2 decimal places. Here, you multiply top and bottom by  10² = 100

\(\frac{0.34}{1}\) × \(\frac{100}{100}\)

=\(\frac{34}{100}\)

Find the Greatest Common Factor (GCF) of 34 and 100, if it exists, reduce the fraction by dividing both numerator and denominator by GCF = 2

Finally, we concluded the value in decimal to fraction   0.34 = \(\frac{17}{50}\)

 

Page 269   Exercise 30  Problem 33

Given:

2.66

To find- Decimal to a fraction or mixed fraction

Here it is given that

2.66

Rewrite the decimal number as a fraction with 1 in the denominator

2.66 = \(\frac{2.66}{1}\)

Multiply to remove 2 decimal places. Here, you multiply the top and bottom by 10²

\(\frac{2.66}{1}\)×\(\frac{100}{100}\)

=  \(\frac{266}{100}\)

Find the Greatest Common Factor (GCF) of 266 and 100, if it exists, reduce the fraction by dividing both numerator and denominator by GCF= 2

Finally, we concluded the value in decimal to fraction  2.66= 2 \(\frac{33}{50}\)

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 269  Exercise 31  Problem 34

Here an integer is given to us.

−13

We have to convert this into an improper fraction.

Any natural number which has to be converted into a fraction we divided by 1. So now −13 is converted −\(\frac{13}{1}\)

Therefore,  −\(\frac{13}{1}\)is the final answer.

 

Page 269   Exercise 32   Problem 35

We are given a mixed fraction.

7 \(\frac{1}{3}\)

We have to convert it into an improper fraction.

To convert 7\(\frac{1}{3}\)into an improper fraction

We multiply 7 with 3 and add 1 to the product.

​(7 × 3) + 1 = 22
​
Therefore, 22 is the numerator.

So, the improper fraction is  \(\frac{22}{3}\)

Finally, we conclude the value in an improper fraction  \(\frac{22}{3}\)

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 269  Exercise 33  Problem 36

We are given a negative decimal value

−3.2.

We have to convert it into a negative improper fraction.

Take the decimal −3.2.

Multiply and divide the decimal by 10.

Finally, we conclude, the value of the final answer is − \(\frac{16}{5}\)

 

Page 269  Exercise 34  Problem 37

Here we are given the time in hours and minutes.

We have to convert it into a decimal.

We are given Nicholas’ time playing the cello as 2 hours and 18 minutes.

First, we convert hours into minutes by multiplying by 60.

2 × 60  = 120 minutes.

Now adding it with the 18-minute

We get 138 minutes.

Now dividing by 60

​⇒  \(\frac{138}{60}\)

​⇒  \(\frac{23}{10}\)

2.3 Hour

Nicholas has been playing the cello for 2.3 hours.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 270  Exercise 35  Problem 38

Given and Find:

We are given fraction and their recurring decimals.

We have to find out which fraction corresponds to 0.88888.

Take option A

1.333333 is not the required answer.

Take option B

0.808080 is not the required answer.

 

Take option C

0.83333 is not the required answer.

Take option D

0.8888 is the required answer.

The required answer is option D.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 270  Exercise 37  Problem 39

Given:

We are given Zoe’s total bill.

We have to find out which mixed fraction corresponds to the decimal given.

Solution:

We take that

12\(\frac{1}{20}\)

To convert it into improper fractions we multiply 20 with 12 and add 1 to the product.

The improper fraction:

\(\frac{241}{20}\)

 

12.05 is the required answer.

Therefore the correct answer is 12.05

 

Page 270   Exercise 38   Problem 40

Given:

We are given a decimal. 5.69

We have to convert it into the nearest tenths place.

We take the decimal 5.69

We look at 9, which is greater than 5.

So we increase the next number by  1.

Now the decimal is rounded off to 5.7

This has been rounded off to the tenths place.

The rounded-off decimal is 5.7

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 270   Exercise 39  Problem 41

Given:

We are given a decimal. 0.05

We have to convert it into the nearest tenths place.

We take the decimal  0.05

We look at 5, which is greater or equal than 5.

So we increase the next number by 1.

Now the decimal is rounded off to 0.1.

This has been rounded off to the tenths place.

The rounded-off decimal is 0.1.

 

Page 270  Exercise 40  Problem 42

Given:

We are given a decimal.

98.99

We have to convert it into the nearest tenths place.

We take the decimal 98.99

We look at 9, which is greater or equal than 5.

So we increase the next number by 1.

Now the decimal is rounded off to This has been rounded off to the tenths place 99.0.

The rounded-off decimal is 99.0.

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 270  Exercise 41   Problem 43

Given and Find:

We are given 3 fractions

\(\frac{1}{2}\)

We have to convert them into decimals and put them onto a number line.

We are given the fraction as \(\frac{1}{2}\)

 

0.5 is decimal.

Therefore we have shown it on the number line

 

Page 270  Exercise 42  Problem 44

Given and Find:

We are given 3 fractions

\(\frac{3}{4}\)

Solution:

We are given the fraction as \(\frac{3}{4}\)

0.75 is a decimal.

Plot these decimals on the number line.

 

 

Therefore we have shown it on the number line

 

 

Glencoe Math Course 2 Volume 1 Common Core Chapter 4 Page 270 Exercise 43  Problem 45

Given and Find:

We are given 3 fractions

\(\frac{2}{3}\)

We have to convert them into decimals and put them onto a number line.

We are given the fraction as \(\frac{2}{3}\)

0.66 is given as the fraction.

Plot these decimals on the number line.

 

 

Therefore we have shown it on the number line