Core Connections Course 1 Student 1st Edition Chapter 1 Introduction and Representation
Core Connections Course 1 Chapter 1 Closure Exercise step-by-step solutions Page 48 Problem 1 Answer
Given the dot pattern,
We need to find figure 4th,5th,6th.First,
we will understand the pattern and then move ahead with same pattern to find next figures.
In the given figure we can see it consist vertical and horizontal dot pattern,
In figure 1, Horizontal dots =2, vertical dots =3
In figure 2, Horizontal dots =3,vertical dots =4
In figure 3, Horizontal dots =4, Vertical dots =5
Read and learn More Core Connections Course 1 Student 1st Edition Solutions
So here if we take Figure number =n then number of horizontal dots will be =n+1 and vertical dots will be =n+2.
So In figure4 , Horizontal dots=5 , Vertical dots=6
In figure5 , Horizontal dots=6 , Vertical dots=7
In figure 6 , Horizontal dots =7, Vertical dots=8
Then the Figure 4 will be as given below
Figure 5 is given below,
Figure 6 is given below
Figure Fourth,
Figure fifth,
Figure sixth,
Core Connections Course 1 Chapter 1 Closure Exercise step-by-step solutions Page 48 Problem 2 Answer
Given Figure show a dot pattern
So we can say that as the figure number changes each one dot is added to the previous pattern in both ways horizontally as well as vertically.
As the figure number changes an additional dot increases in the previous pattern in both ways horizontally as well as vertically.
solutions for Core Connections Course 1 Chapter 1 Closure Introduction and Representation Page 48 Problem 3 Answer
We have given situation where Lena’s mother ask her to count number of pennies in the jar.
We need to find out numerical expression which represent Lena’s way of counting.
As per the question when Lena counted she said that she made nine stack of five pennies and two left, which means the numerical expression will be multiplication of nine stack with five pennies and then add two.
Given that Lena counted she said that she made nine stack of five pennies and two left, which means the numerical expression will be multiplication of nine stack with five pennies and then add two.
So it can be shown as following
=(9∗5)+2
Numerical expression for Lena’s counting =(9∗5)+2
Core Connections Course Chapter 1 Page 48 Problem 4 Answer
We have given situation where Lena’s mother ask her to count number of pennies in the jar.
We need to find out numerical expression which represent Lena’s mother’s way of counting.
As per the question her mother said she made seven stack of six pennies each and four left ,that means the numerical expression will be Multiplication of Seven stack with six pennies and then add four to it.
Given in question that mother said she made seven stacks of six pennies each and four left, that means the numerical expression will be Multiplication of Seven stacks with six pennies and then add four to it.
So, the number of pennies will be calculated as=( number of stacks∗number of pennies in each stack) + remaining pennies
=(7⋅6)+4
The numerical expression for Lena’s Mother’s counting is =(7⋅6)+4
Core Connections Course 1 Student 1st Edition Chapter 1 Closure Exercise guide Page 48 Problem 5 Answer
We have given situation where Lena’s mother ask her to count number of pennies in the jar.
We have to verify that while Lena’ counting is different from her mother’s counting.
First, we will calculate number of pennies as per Lena’s counting and then her mother’s counting and then we can verify whether Lena was wrong or not.
As per Lena’s counting the numerical expression is =(9∗5)+2
That means total pennies as per Lena’s counting is =45+2⇒47 and as per Lena’s mother’s counting the numerical expression is =(7∗6)+4
That means total pennies as per her mother’s counting is =42+4⇒46
Hence , Lena was correct as her numerical expression is more than her mother’s.
Lena was correct.
Core Connections Course Chapter 1 Page 48 Problem 6 Answer
We have given situation where Lena’s mother ask her to count number of pennies in the jar.
We need to compare counting of both Lena’s and her mother’s.
We earlier found out that total of Lena’s counting is =47
Total of Lena’s Mother’s counting is=46
Hence, Total of Lena’s counting >
Lena’s Mother’s Counting.
Total of Lena’s counting >
Total of Lena’s mother’s counting.
Chapter 1 Closure Introduction and Representation Core Connections Course 1 explained Page 48 Problem 7 Answer
We have given a situation where Amanda’s little brother is learning about even and odd numbers.
Timmy said “Six is both even and odd because 2 is even and goes into 6 and 3 is odd and goes into 6.”
We need to correct Timmy’s statement.
As per Timmy said , six is both even and odd number because it is divisible by both 2,3.
But he is wrong because the number which are divisible by three are multiple of three not odd numbers.
Even number refers to those numbers which are divisible by two and Odd numbers are the numbers which are not divisible by two.
So, six is divisible by two that means six is even number . And me always keep in mind that a number can either even or odd, no number can be both.
Even number refers to those numbers which are divisible by two and Odd numbers are the numbers which are not divisible by two.
Core Connections Course Chapter 1 Page 49 Problem 8 Answer
We have given a figure
We need to find out perimeter and area of the given figure.
We will use Sum all the outer length (sum of all sides) to find the perimeter.
To find area we will multiply area of one box with total number of boxes.
First we will name every corner of the image so it will be easy to understand And length of one box is one unit.
Now to find perimeter we do sum of length of all sides
Perimeter=AB+BC+CD+DE+EF+FG+GH+HI+IJ
Since we can see AB=2units
BC=1unit
CD=1unit
DE=1unit
EF=1unit
FG=1unit
GH=3units
HI=1unit
IJ=1unit
JA=2units
Now putting values in formula ,
Therefore , Perimeter =2+1+1+1+1+1+3+1+1+2
⇒14 units area of one box =side*side =1∗1⇒1sq. unit
Area of given figure = number of boxes *Area of one box
=8∗1sq. unit
⇒8sq. units
Perimeter of the given figure is =14units and Area is =8sq. units
Core Connections Course Chapter 1 Page 49 Problem 9 Answer
We have given figure
We need to find out its perimeter and area.
Since it is a rectangle , the perimeter will be 2(l+b) and area will be =l∗b
In the given figure length =5units,breadth =4units
Perimeter=2(l+b)
=2(5+4)
=2∗9⇒18 units
Area =l∗b
=5∗4⇒20sq. units
Perimeter of the given figure =18units, Area=20sq. units
free Core Connections Course 1 Chapter 1 Closure Exercise Introduction and Representation solutions Page 49 Problem 10 Answer
We have given figure
We need to find out its perimeter and area.
Since it is a rectangle , the perimeter will be 2(l+b) and area will be =l∗b
Given in the figure, Length of rectangle = 8cm, breadth of rectangle = 15cm
Perimeter of rectangle=2(l+b)
=2(8+15)
=2∗23⇒46cm
Area of rectangle =l∗b
=8∗15⇒120cm2
Perimeter of given figure=46cm, Area=120cm2
Core Connections Course Chapter 1 Page 49 Problem 11 Answer
Given figure
We need to reshape this figure so that the perimeter will be larger.First we will rearrange the boxes and then show that perimeter is larger.
Arranging given figure in the following manner
We found earlier that the perimeter of figure (a) is =14 units
Now the perimeter of this new arranged figure =AB+BC+CD+DE+EF+FG+GH+HI+IJ+JK+KL+LA
=2+1+1+1+1+2+1+2+2+1+1+1
=16units
Now perimeter of this new figure is more than given (a) figure.
The rearranged shape is
and its perimeter is =16units
Core Connections Course Chapter 1 Page 49 Problem 12 Answer
We are given multiplication sentence in the question.
We have to find the missing number that makes the sentence true.
We can do this by using multiplication and division.
Given, 12⋅x=180
Dividing both sides by 12, (12⋅x)
12 = 180/12
Hence, x = 15.
Therefore, the missing number is 15.
The correct sentence will be 12 ⋅15 = 180
how to solve Core Connections Course 1 Chapter 1 Closure Exercise problems Page 49 Problem 13 Answer
We are given mathematical sentence in the question.
96/?=12
We have to find the missing number that makes the sentence true.We can do this by using multiplication and division.
Given, 96/x = 12
By transposing the equation, 96/12=x
Hence, x = 8
Therefore, the missing number is 8.
The correct sentence will be 96/8 =12
Core Connections Course Chapter 1 Page 49 Problem 14 Answer
We are given a multiplication sentence in the question.
7.?=98
We have to find the missing number that makes the sentence true.We can do this by using multiplication and division.
Given, 7 . x = 98
By transposing the equation, x = 98/7
Hence, x = 14.
Therefore, the missing number is 14 to make the sentence true.
The correct sentence is 7 ⋅ 14 = 98
worked examples for Core Connections Course 1 Chapter 1 Closure Exercise Introduction and Representation Page 49 Problem 15 Answer
We are given mathematical sentence in the question.
We have to find the missing number that makes the sentence true.
We can do this by using multiplication and division.
?/9=11
Given, x/9 = 11
By transposing the equation, we get x = 9 × 11
Hence, x = 99
Therefore, the missing number to make the sentence true is 99.
The correct sentence is 99/11 = 9
Core Connections Course Chapter 1 Page 49 Problem 16 Answer
We were given some mathematical sentences and were asked to find the missing number to make the sentence true.
In this question, depending on how difficult we found those previous questions we are given some tasks.
We can do this by first coloring or shading the bar that represents our level of understanding.
I am the at the level of understanding 8.
Since my level of understanding is more than 5, I have to make a new problem that is similar and more challenging than that problem and solve it.
A new problem could be – 100
? + 2 = 27
100/? = 25
? = 4
Hence, a new problem was created and solved.