Geometry Homework Practice Workbook 1st Edition Chapter 2 Exercise 2.6 Inductive Reasoning and Conjecture

Geometry Homework Practice Workbook 1st Edition Chapter 2 Inductive Reasoning and Conjecture

Page 25 Problem 1 Answer

In this question, we have been given the value: 80=m∠A

We need to state the property that justifies the statement.

By using Inductive Reasoning and Conjecture, we will calculate the result.

As we see this statement uses the symmetric property.

The symmetric property of equality states that regardless of which side of an equal sign they are on, both sides are equal.

Hence, the given statement 80=m∠A, then 80=m∠A uses the symmetric property.

It states that regardless of which side of an equal sign they are on, both sides are equal.

Page 25 Problem 2 Answer

In this question, we have been given the value:

RS=TU

TU=YP

RS=YP

We need to state the property that justifies the statement.

By using Inductive Reasoning and Conjecture, we will calculate the result.

As we see this statement uses the transitive property of equality.

The transitive property of equality states that if a is related to b and b is related to c, then a is related to c.

Hence, the given statement RS=TU and TU=YP, then RS=YP uses the transitive property of equality. It states that if a is related to b and b is related to c, then a is related to c.

Page 25 Problem 3 Answer

In this question, we have been given the value:

7x=28

x=4

We need to state the property that justifies the statement.

By using Inductive Reasoning and Conjecture, we will calculate the result.

As we see this statement uses the division property of equality.

It states that when both sides of an equation are divided by the same non-zero number, the two sides remain equal, according to the division property of equality.

Hence, the given statement 7x=28,  then x=4 uses the division property of equality.

It states that when both sides of an equation are divided by the same non-zero number, the two sides remain equal, according to the division property of equality.

Page 25 Problem 4 Answer

In this question, we have been given the value:

VR+TY=EN+TY

VR=EN​

We need to state the property that justifies the statement.

By using Inductive Reasoning and Conjecture, we will calculate the result.

As we see this statement uses the subtraction property of equality.

The subtraction property of equality states that if one side of an equation is subtracted, the other side must likewise be subtracted to maintain the equation the same.

Hence, the given statement VR+TY=EN+TY,  then VR=EN uses the subtraction property of equality.

It states that if one side of an equation is subtracted, the other side must likewise be subtracted to maintain the equation the same.

Page 25 Problem 5 Answer

We are given m∠1=30 & m∠1=m∠2

​We have to justify the statement that if the above two equations are true then m∠2=30

We will be using some algebraic properties to justify the required statement.

We are given m∠1=30&

m∠1=m∠2​

By using transitive property we can say that m∠2=30

Thus, the transitive property is shown by the statement if ​m∠1=30&

m∠1=m∠2 then m∠2=30

Page 25 Problem 6 Answer

We are given a table as shown

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture

Also, we are given an equation 8x−5=2x+1

We have to complete the table and prove that x=1

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 6 1

We will be using some algebraic properties to complete the table and prove the required result

We are given a table and an equation8x−5=2x+1

After completing the table we get,

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 6 2

Here, the highlighted portion in the table represent the blanks given in the table of question

Thus, we have completed the table and proved x=1 for the given equation 8x−5=2x+1

Page 25 Problem 7 Answer

We are given a figure and PQˉ≅QSˉ&QSˉ=STˉ

We have to prove PQ=ST

We will be using some algebraic properties and congruent lines concept to prove the same.

We are given a figure

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 7

Two-column proof to verify the conjecture is

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 7 1

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 7 2

Hence, we have written a two-column proof to verify the conjecture “if PQˉ≅QSˉ&QSˉ≅STˉ then

PQ=ST”, for the given figure

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 7 3

The two-column proof is

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 7 4

Page 26 Problem 8 Answer

In this question, we have been given the value:

m∠ABC+m∠CBD=90

m∠ABC=3x−5

m∠CBD=x+1/2

We need to write a two-column proof to verify each conjecture.

By using Inductive Reasoning and Conjecture, we will calculate the result.

We analyze the diagram

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 8

Since the ∠ABC and m∠CBD are complementary angles.

We substitute the values

m∠ABC+m∠CBD=90

3x−5+x+1/2=90

6x−10+x+1=90×2

7x−9=180

Further solving, we get

7x=189

x=189/7

x=27

​Hence, the value of x=27.

Since the ∠ABC and ∠CBD are complementary angles.

We substitute the values and analyze the diagram

Geometry, Homework Practice Workbook, 1st Edition, Chapter 2 Inductive Reasoning and Conjecture 8 1

Page 26 Problem 9 Answer

In this question, we have been given the value: I=prt

We need to solve the formula for r and justify each step.

By using Inductive Reasoning and Conjecture, we will calculate the result.

We divide the whole formula by pt to solve for r

I/p×t=p×r×t/p×t

I/p×t=r

​Hence, the formula for r is r=I/p×t. Since we divide the whole formula by pt and using the formula of simple interest.

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