HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Multiplying and Dividing Integers
Page 9 Problem 1 Answer
In this question it is given that the expression is 4(−20).
It is required to calculate the product of the given expression.
The product is in the form (+a)(−b)=−ab
Hence, 4(−20)=−80.
The product is 4(−20)=−80.
HMH Grade 7 Practice Fluency Workbook Chapter 2 Exercise 2.1 Solutions Page 9 Problem 2 Answer
In this question it is given that the expression is −6(12).
It is required to calculate the product of the given expression.
The product is in the form (−a)(+b)=−ab
Hence−6(12)=−72.
The product is −6(12)=−72.
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HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 3 Answer
In this question it is given that the expression is13(−3).
It is required to calculate the product of the given expression.
The product is in the form (+a)(−b)=−ab
Hence 13(−3)=−39.
The product is 13(−3)=−39.
Multiplying And Dividing Integers Exercise 2.1 Chapter 2 Answers HMH Grade 7 Workbook Page 9 Problem 4 Answer
In this question it is given that the expression is −10(0).
It is required to calculate the product of the given expression.
The product is in the form (−a)(+b)=−ab
Hence−10(0)=0.
The product is −10(0)=0
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 5 Answer
Step-By-Step Solutions For Exercise 2.1 Multiplying And Dividing Integers HMH Grade 7 Practice Workbook” Page 9 Problem 6 Answer
In this question, it is given that the expression is −9(−21).
It is required to calculate the product of the given expression.
The product is in the form (−a)(−b)=+ab
Hence −9(−21)=189.
The product is −9(−21)=189.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 7 Answer
In this question it is given that the expression is18(−4).
It is required to calculate the product of the given expression.
The product is in the form(+a)(−b)=−ab
Hence 18(−4)=−72.
The product is 18(−4)=−72.
Exercise 2.1 Multiplying And Dividing Integers Solutions For HMH Middle School Grade 7 Workbook Page 9 Problem 8 Answer
In this question , it is given the product10(8).
It is required to evaluate each product.
To solve this , Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign.
The given expression is 10(8)
Performing the multiplication.
Multiplying the absolute values of the two numbers.
The sign of the result is because the numbers which are getting multiplied is of same sign.
10(8)=10⋅8
10(8)=80
The value of 10(8) is 80.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 9 Answer
In this question , it is given the product9(−6).
It is required to evaluate each product.
To solve this , Perform the multiplication.
Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign.
The given expression is 9(−6)
Performing the multiplication.
Multiplying the absolute values of the two numbers.
The sign of the result is −because the numbers which are getting multiplied is of different sign.
9(−6)=9⋅−6
9(−6)=−54
The value of 9(−6) is −54.
Examples Of Problems From Exercise 2.1 Multiplying And Dividing Integers In HMH Grade 7 Workbook Page 9 Problem 10 Answer
In this question, it is given the product −7(−7).
It is required to evaluate each product.
To solve this, Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is the same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign.
The given expression is−7(−7)
Performing the multiplication.
Multiplying the absolute values of the two numbers.
The sign of the result is because the numbers that are getting multiplied is of the same sign.
−7(−7)=−7⋅−7
−7(−7)=49
The value of −7(−7) is 49.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 11 Answer
In this question, it is given that you play a game where you score −6 for the first turn and on each of the next 3 turns.
It is required to tell what will be the score after those 4 turns.
To solve this, write a mathematical expression to represent the score after 4 turns.
This will be the product of −6 and 4. Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is the same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign.
It is given that you play a game where you score −6 for the first turn and on each of the next 3 turns.
That means −6 was scored 4 times.
The total will be 4 times of −6.
This will be the product of −6 and 4.,Perform the multiplication.
−6⋅4=−24
The sign will be − because the numbers being multiplied are of different signs.
The total score after 4 turns is −24.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 12 Answer
In this question it is given that the outdoor temperature declines 3 degrees each hour for 5 hours.
It is required to find the change in temperature at the end of those 5 hours.
To solve this, write a mathematical expression to represent the change in temperature at the end of those 5 hours.
This will be the product of −3 and 5. Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign.
It is given that the outdoor temperature declines 3 degrees each hour for 5 hours.
That means the temperature declined −3 degrees 5 times.
This will be the product of −3 and 5.
Perform the multiplication.
−3⋅5=−15
The sign will be − because the numbers being multiplied are of different signs.
The change in temperature at the end of those 5 hours is 15∘.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 13 Answer
In this question it is given you have dollar 200 in a savings account. Each week for 8 weeks, you take out dollar 18 for spending money.
It is required to find how much money will be there in the account at the end of 8 weeks.
To solve this, write a mathematical expression to represent the money that will be there in the account at the end of 8 weeks.
The total money spend from the account will be the product of 18 and 8.
Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign.
Subtract this amount from the total money in the account to get the amount of money left in account at the end of 8 weeks.
Write a mathematical expression to represent the money that will be there in the account at the end of 8 weeks.
The total money spend from the account will be the product of 18 and 8.
Subtract this amount from the total money in the account to get the amount of money left in account at the end of 8 weeks.
200−8(18)
The sign will be − because the numbers being multiplied are of different signs.
200−144=56
Therefore , there will be 56 dollars in the account at the end of 8 weeks.
There will be 56 dollars in the account at the end of 8 weeks.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 14 Answer
In this question it is given that the outdoor temperature was 8 degrees at midnight.
the temperature declined 5 degrees during each of the next 3 hours.
It is required to find the temperature at 3 a.m.
To solve this, write a mathematical expression to represent the temperature at 3 a.m.
This will be the product of 3 and 5. Perform the multiplication.
Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be −.
Write the evaluated number with the appropriate sign. Subtract this number from 8 to get the temperature at 3 a.m.
It is given that the outdoor temperature was 8 degrees at midnight . The temperature declined 5 degrees during each of the next 3 hours.
Write a mathematical expression to represent the temperature at 3 a.m.
8−3(5)
Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be −.8−15=−7
The temperature at 3 a.m. is −7∘.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 9 Problem 15 Answer
In this question it is given that the price of the stock was 325 a share. The price of the stock went down 25 each week for 6 weeks.
It is required to find the price of the stock at the end of 6 weeks.
To solve this, write a mathematical expression to represent the price of the stock at the end of 6 weeks.
The price decreased of the stock will be the product of 25 and 6 weeks. Subtract this value from the original value of stock to find the price of the stock at the end of 6 weeks.
It is given that the price of the stock was 325 a share.
The price of the stock went down 25 each week for 6 weeks.
write a mathematical expression to represent the price of the stock at the end of 6 weeks.
The price decreased of the stock will be the product of 25 and 6 weeks.
Subtract this value from the original value of stock to find the price of the stock at the end of 6weeks.
Perform the multiplication. Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be +otherwise it will be −.
325−6(25)=325−150
325−6(25)=175
Therefore, the price of the stock at the end of 6 weeks is 175.
The price of the stock at the end of 6 weeks is 175.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 16 Answer
In this question , it is given the product 1(−2).
It is required to evaluate each product.
To solve this , Perform the multiplication.
Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be + otherwise it will be−.
Write the evaluated number with the appropriate sign.
The given expression is 1(−2)
Performing the multiplication.
Multiplying the absolute values of the two numbers.
The sign of the result is −because the numbers which are getting multiplied are of different sign.
1(−2)=1⋅−2
1(−2)=−2
The value of 1(−2) is −2.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 17 Answer
In this question, it is given the product −6(−3).
It is required to evaluate each product.
To solve this , Perform the multiplication.
Multiply the absolute values of the two numbers.
If the sign of the two numbers being multiplied is same, then the sign of the result will be+ otherwise it will be −.
Write the evaluated number with the appropriate sign.
The given expression is−6(−3)
Performing the multiplication.
Multiplying the absolute values of the two numbers.
The sign of the result is+because the numbers which are getting multiplied is of same sign.
−6(−3)=−6⋅−3
−6(−3)=18
The value of −6(−3) is 18.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 18 Answer
In the question, the expression is given which is (5)(−1).
It is required to find out the product of the given expression.
To solve the question multiply the (5) by (−1).
(5)(−1) is the given expression.
(5)(−1)=−(5.1) =−5
(Multiply the absolute values of the two numbers, the sign of the product is minus
Because the numbers that are going to multiply have different signs)
The product of the given expression is −5.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 19 Answer
In the question, the expression is given which is (−9)(−6).
It is required to find out the product of the given expression.
To solve the question, multiply the (−9) by (−6).
(−9)(−6) is the given expression.
(−9)(−6)=9.6
(−9)(−6)=9.6
(Multiply the absolute values of the two numbers; the sign of the product =54
The product of the given expression is 54.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 20 Answer
In the question, the expression is given which is 11(4).
It is required to find out the product of the given expression.
To solve the question, multiply the 11 by (4).
In the question, the expression is given which is 11(4).
It is required to find out the product of the given expression.
To solve the question, multiply the 11 by (4).
The product of the given expression is 44.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 21 Answer
In the question, it is given a situation that you are playing a game and start from 0. Then, score −8 points on each 4 turns.
It is required to write a mathematical expression to represent the situation and then find the score after those 4 turns.
To solve the question understand the situation and then write the mathematical expression.
Let 4(−8) be the mathematical expression to represent the score after 4 turns.
4(−8)=−(4.8)
4(−8) =−32
(Multiply the absolute values of the two numbers; the sign of the product is minus because the numbers that are going to multiply have different signs)
The score after 4 turns is −32 points.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 10 Problem 22 Answer
In the question, it is given that a mountaineer descends a mountain for 5 hours. On average, she climbs down 500 feet each hour.
It is required to write a mathematical expression to represent the situation and find what is her change in elevation after 5 hours.
To solve the question, understand the situation and then write the mathematical expression.
Let 5(−500) be the mathematical expression to represent the change of elevation after 5 hours.
5(−500)=−(5.500)
5(−500) =−2500
(Multiply the absolute values of the two numbers; the sign of the product is minus because the numbers that are going to multiply have different signs)
The change of elevation after 5 hours is −2500 feet.