HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Multiplying and Dividing Integers
HMH Grade 7 Practice Fluency Workbook Chapter 2 Exercise 2.3 Solutions Page 13 Problem 1 Answer
It is given the expression (−3)(−2)+8.
It is required to simplify the given expression.
To simplify the given expression, first solve the brackets by using multiplication and then use division to get the required answer.
Solving the brackets by using multiplication and then using division.
(−3)(−2)+8=6+8
(−3)(−2)+8 =14
So, the value of the expression turns out to be 14.
HMH Grade 7 Practice Fluency Workbook Chapter 2 Exercise 2.3 Solutions Page 13 Problem 2 Answer
The given expression is (−18)÷3+(5)(−2).
It is required to simplify the given expression
To do this apply the BODMAS rule and simplify the expression.
The given expression is (−18)÷3+(5)(−2).
First simplifying the brackets by multiplying and dividing the terms in the above expression.
(−18)÷3+(5)(−2)=−6−10
So, the solution will become−16.
The value after simplifying the expression is−16.
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Multiplying And Dividing Integers Exercise 2.3 Chapter 2 Answers HMH Grade 7 Workbook Page 13 Problem 1 Answer
Multiplying And Dividing Integers Exercise 2.3 Chapter 2 Answers HMH Grade 7 Workbook Page 13 Problem 3 Answer
The given expression is 24÷(−6)(−2)+7.
It is required to simplify the given expression.
To do this apply the BODMAS rule and simplify the expression.
The given expression is 24÷(−6)(−2)+7.
First simplifying the brackets by multiplying the terms:
24÷(−6)(−2)+7=24÷12+7
Now solving the terms for division:
24÷12+7=2+7
So, the solution will become 9.
The value after simplifying the expression is 9.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 13 Problem 4 Answer
The given expression is 4(−8)+3.
It is required to simplify the given expression.
To do this apply the BODMAS rule and simplify the expression.
The given expression is4(−8)+3.
First simplifying the brackets by multiplying the terms.
4(−8)+3=−32+3
So, the solution will become−29.
The value after simplifying the expression is −29.
Step-By-Step Solutions For Exercise 2.3 Multiplying And Dividing Integers Hmh Grade 7 Practice Workbook Page 13 Problem 5 Answer
The given expression is (−9)(0)+(8)(−5).
It is required to simplify the given expression.
To do this apply the BODMAS rule and simplify the expression.
The given expression is (−9)(0)+(8)(−5).
First simplifying the brackets by multiplying the terms.
(−9)(0)+(8)(−5)=0−40
So, the solution will become−40.
The value after simplifying the expression is −40.
Exercise 2.3 Multiplying And Dividing Integers Solutions For HMH Middle School Grade 7 Workbook Page 13 Problem 6 Answer
It is given that a boat would have to be lowered 12 feet at Amsterdam, 11 feet at tribes Hill, and 8 feet at Randall.
It is required to evaluate by how much the elevation of the boat changes between Amsterdam and Randall.
Apply the BODMAS and solve it.
Form the expression 12ft. at Amsterdam, 11ft at Tribes Hill, 8ft at Randall.
So, according to given value, −12+(−11)+(−8).
Solving the operator.
−12+(−11)+(−8)=−(12+11+18)
−12+(−11)+(−8) =−31
Hence, it is lowered by 31ft.
Examples Of Problems From Exercise 2.3 Multiplying And Dividing Integers In HMH Grade 7 Workbook Page 13 Problem 7 Answer
It is given that Mrs. Armour bought 7 pairs of socks for $3 each, and a sweater for $12 each.
She found $5 on the sidewalk.
It is required to evaluate the change in amount of money
Apply the BODMAS and solve it.
From the expression, 7 pairs of socks for $3 each.
A sweater for $12 each. $5 on the sidewalk.
So, according to the given value, 7(−3)+(−12)+5.
Solve the expression.
7(−3)+(−12)+5
7(−3)+(−12)+5 =−21−12+5
7(−3)+(−12)+5 =−33+5
7(−3)+(−12)+5 =−28
Hence, the value will be decreased by 28.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 8 Answer
It is given −4+(3)(−8)+7.
It is required to find the order and solve it accordingly.
Apply the bodmas and solve it.
Write the given expression.
−4+(3)(−8)+7
Multiply in order from left to right.
−4+(3)(−8)+7=−4−24+7
Add and subtract in order from left to right.
−4−24+7=−28+7
−4−24+7 =−21
The operation that is used first is multiplication. The value of −4+(3)(−8)+7 is −21.
Common Core Chapter 2 Exercise 2.3 Multiplying and Dividing Integers detailed solutions HMH Grade 7 Workbook Page 14 Problem 9 Answer
It is given −3+(−8)−6.
It is required to find the order and solve it accordingly.
Apply the bodmas and solve it.
Write the given expression −3+(−8)−6.
Add and subtract in order from left to right.
−3+(−8)−6=−11−6
−3+(−8)−6 =−17
The operation that is used first is addition. The value of −3+(−8)−6 is −17.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 10 Answer
It is given 16+72÷(−8)+6(−2).
It is required to find the order and solve it accordingly.
Apply the BODMAS and solve it.
Write the given expression.
16+72÷(−8)+6(−2)
Multiply and Divide in order from left to right.
16+72÷(−8)+6(−2)=16+(−9)+(−12)
Add and subtract in order from left to right.
16+(−9)+(−12)=16−9−12
16+(−9)+(−12) =16−21
16+(−9)+(−12) =−5
The operation that is used first is division. The value of 16+72÷(−8)+6(−2) is−5
Student Edition Chapter 2 Exercise 2.3 Multiplying and Dividing Integers HMH Grade 7 Workbook guide Page 14 Problem 11 Answer
It is given 17+8+(−16)−34.
It is required to find the order and solve it accordingly.
Apply the Bodmas and solve it.
Write the given expression.
17+8+(−16)−34
Add and subtract in order from left to right.
17+8+(−16)−34=25+(−16)−34
17+8+(−16)−34 =25−16−34
17+8+(−16)−34 =9−34
17+8+(−16)−34 =−25
The operation that is used first is addition. The value of 17+8+(−16)−34 is −25.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 12 Answer
It is given−8+13+(−24)+6(−4).
It is required in this problem to name the operation that is to be done first.
In order to name this problem, the operation that is to be done first, apply the order of operations.
First, apply the order of operations and perform multiplication from left to right.
−8+13+(−24)+6(−4)=−8+13−24−24
Further, perform addition and subtraction from left to right.
−8+13−24−24=−56+13
−8+13−24−24 =−43
Hence, the first operation done is a multiplication operation.
Hence, as required in the problem, multiplication operation is the operation that is done first.
Step-by-step answers for Exercise 2.3 Multiplying and Dividing Integers HMH Grade 7 Practice Workbook Page 14 Problem 13 Answer
It is given 12÷(−3)+7(−7).
It is required in this problem to name the operation that is to be done first.
In order to name this problem, the operation that is to be done first, apply the order of operations.
At first, apply the order of operations, perform division and then multiplication from left to right.
12÷(−3)+7(−7)=−4+(−49)
Further, perform addition and subtraction from left to right.
−4+(−49)=−53
Hence, the first operation done is division operation.
Hence, as required in the problem, division operation is the operation that is done first.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 14 Answer
It is given (−5)6+(−12)−6(9).
It is required in this problem to name the operation that is to be done first.
In order to name this problem, the operation that is to be done first, apply the order of operations.
First, apply the order of operations and perform multiplication from left to right.
(−5)6+(−12)−6(9)=−30+(−12)−54
Further, perform addition and subtraction from left to right.
−30+(−12)−54=−96
Hence, the first operation done is a multiplication operation.
Hence, as required in the problem, multiplication operation is the operation that is done first.
Page 14 Problem 15 Answer
It is given 14−(−9)−6−5.
It is required in this problem to name the operation that is to be done first.
In order to name this problem, the operation that is to be done first, apply the order of operations.
At first, apply the order of operations, perform addition and subtraction from left to right.
14−(−9)−6−5=14+9−6−5
14−(−9)−6−5 =23−11
14−(−9)−6−5 =12
Hence, the first operation done is an addition operation.
Hence, as required in the problem, addition operation is the operation that is done first.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 16 Answer
It is given (−6)+5(−2)+15.
It is required in this problem to find the value of a given expression.
In order to find in this problem the value of a given expression, apply the order of operations.
First, apply the order of operations and perform multiplication from left to right.
(−6)+5(−2)+15=−6−10+15
Further, perform addition and subtraction from left to right.
−6−10+15=−1
Hence, (−6)+5(−2)+15=−1.
Hence, the value of the expression given is (−6)+5(−2)+15=−1.
Hence, as required in the problem, the value of the expression given is (−6)+5(−2)+15=−1.
Page 14 Problem 17 Answer
It is given (−8)+(−19)−4.
It is required in this problem to find the value of a given expression.
In order to find in this problem the value of a given expression, apply the order of operations.
At first, apply the order of operations, perform addition and subtraction from left to right.
(−8)+(−19)−4=−8−19−4
(−8)+(−19)−4 =−31
Hence, (−8)+(−19)−4=−31.
Hence, the value of the expression given is (−8)+(−19)−4=−31.
Hence, as required in the problem, the value of the expression given is (−8)+(−19)−4=−31.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 18 Answer
It is given 3+28÷(−7)+5(−6).
It is required in this problem to find the value of a given expression.
In order to find in this problem the value of a given expression, apply the order of operations.
At first, apply the order of operations, perform division first and then multiplication from left to right.
3+28÷(−7)+5(−6)=3+(−4)+(−30)
Further, perform addition and subtraction from left to right.
3+(−4)+(−30)=3−4−30
3+(−4)+(−30) =−31
Hence, 3+28÷(−7)+5(−6)=−31.
Hence, the value of the expression given is 3+28÷(−7)+5(−6)=−31.
Hence, as required in the problem, the value of the expression given is 3+28÷(−7)+5(−6)=−31.
Page 14 Problem 19 Answer
It is given 15+32+(−8)−6.
It is required in this problem to find the value of a given expression.
In order to find in this problem the value of a given expression, apply the order of operations.
At first, apply the order of operations, perform addition and subtraction from left to right.
15+32+(−8)−6=15+32−8−6
15+32+(−8)−6 =47−14
15+32+(−8)−6 =33
Hence, 15+32+(−8)−6=33.
Hence, the value of the expression given is 15+32+(−8)−6=33.
Hence, as required in the problem, the value of the expression given is 15+32+(−8)−6=33.
HMH Middle School Grade 7 Practice Fluency Workbook 1st Edition Chapter 2 Page 14 Problem 20 Answer
It is given (−5)+22+(−7)+8(−9).
It is required in this problem to find the value of a given expression.
In order to find in this problem the value of a given expression, apply the order of operations.
At first, apply the order of operations, perform multiplication from left to right.
(−5)+22+(−7)+8(−9)=−5+22−7+(−72)
Further, perform addition and subtraction from left to right.
−5+22−7+(−72)=−5−7−72+22
−5+22−7+(−72) =−84+22
−5+22−7+(−72) =−62
Hence, (−5)+22+(−7)+8(−9)=−62.
Hence, the value of the expression given is (−5)+22+(−7)+8(−9)=−62.
Hence, as required in the problem, the value of the expression given is (−5)+22+(−7)+8(−9)=−62.
Page 14 Problem 21 Answer
It is given 21÷(−7)+5(−9).
It is required in this problem to find the value of a given expression.
In order to find in this problem the value of a given expression, apply the order of operations.
At first, apply the order of operations, perform division first and then multiplication from left to right.
21÷(−7)+5(−9)=(−3)+(−45)
Further, perform addition and subtraction from left to right.
(−3)+(−45)=−3−45
(−3)+(−45) =−48
Hence, 21÷(−7)+5(−9)=−48.
Hence, the value of the expression given is 21÷(−7)+5(−9)=−48.
Hence, as required in the problem, the value of the expression given is 21÷(−7)+5(−9)=−48.