Holt Algebra 1 Homework and Practice Workbook 1st Edition Chapter 1 Exercise 1.2

Holt Algebra 1 Homework and Practice Workbook 1st Edition Chapter 1

Page 2 Problem 1 Answer

Given: Expression is −6+(−8).

To add or subtract the given expression using a number line.

Start at 0. Move left to -6.To add -8, move left 8 units.

The given expression can be added using a number line as below. Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 1

Mathematically,−6+(−8)=−14

The value of the given expression is −6+(−8)=−14.

Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 1 1

Page 2 Problem 2 Answer

Given: Expression is 10+(−4).

To add or subtract the given expression using a number line.

Start at 0. Move right to 10.To add -4, move left 4 units.

The given expression can be added using a number line as below. Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 2

Mathematically,10+(−4)=6

The value of the given expression is 10+(−4)=6.

Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 2 1

Page 2 Problem 3 Answer

Given: Expression is−2−(−6).

To add or subtract the given expression using a number line.

Start at 0. Move left to -2. To subtract -6, move right 6 units.

The given expression can be added using a number line as below. Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 3

Mathematically,−2−(−6)=4

The value of the given expression is−2−(−6)=4.

Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 3 1

Page 2 Problem 4 Answer

Given: Expression is−7+7.

To add or subtract the given expression using a number line.

Start at 0. Move left to -7.To add 7, move right 7 units.

The given expression can be added using a number line as below. Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 4

Mathematically,−7+7=0

The value of the given expression is−7+7=0.

Holt Algebra 1 Homework and Practice Workbook, 1st Edition, Chapter 1 4 1

Page 2 Problem 5 Answer

Given: Expression is 24.6+(−45.5).

To add the given expression.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

Absolute difference of 45.5 and 24.6 is − 45.5−24.6=20.9

Using the sign of a number with greater value we get -24.6+(−45.5)=−20.9

The addition of 24.6+(−45.5)=−20.9 .

Page 2 Problem 6 Answer

Given: Expression is −3/8+5.

To add the given expression.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

Absolute difference of 3/8 and 5 is -3/8−5=−37/8

Using the sign of a number with greater value we get-

−3/8+5=37/8

The addition of−3/8+5=37/8.

Page 2 Problem 7 Answer

Given: Expression is a+(−14) and a=16.

To add the given expression for the given value of a.

First substitute 16 for a.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

On substituting the value of a in the given expression we get -16+(−14)

Absolute difference of 16 and 14 is − 16−14=2

Using the sign of a number with greater value we get -16+(−14)=2

The addition of a+(−14) for a=16 is 2.

Page 2 Problem 8 Answer

Given: Expression is −3.3+x and x=−9.1.

To add the given expression for the given value of x.

First substitute -9.1 for x.When the signs of the numbers are the same, find the sum of their absolute values.

Both numbers are negative, so the sum is negative.

On substituting the value of x in the given expression we get -−3.3+(−9.1)

Absolute sum of 3.3 and 9.1 is -3.3+9.1=12.4

Both numbers are negative, so the sum is negative.

Therefore, −3.3+(−9.1)=−12.4

The addition of −3.3+x and x=−9.1 is −12.4

Page 2 Problem 9 Answer

Given: Expression is 12−(−16).

To subtract the given expression.

First write the expression in the form of addition.

When the signs of the numbers are the same, find the sum of their absolute values.

Both numbers are positive, so the sum is positive.

On writing the given expression as addition we get -12+16

Absolute sum of 12 and 16 is -12+16=28

Both numbers are positive, so the sum is positive.

Therefore,12−(−16)=28

The subtraction of 12−(−16)=28.

Page 2 Problem 10 Answer

Given: Expression is 8.3−10.7.

To subtract the given expression.

First write the expression in the form of addition.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

On writing the given expression in the form of addition we get -8.3+(−10.7)

Absolute difference of 8.3 and 10.7 is -10.7−8.3=2.4

Using the sign of a number with greater value we get-8.3−10.7=−2.4

The subtraction of 8.3−10.7=−2.4.

Page 2 Problem 11 Answer

Given: Expression is −2/3−51/3.

To subtract the given expression.

First convert the given expression into proper fraction and then write it in the form of addition.

When the signs of the numbers are the same, find the sum of their absolute values.

Both numbers are negative, so the sum is negative.

On writing the given expression as proper fraction and in the form of addition we get -−2/3+(−16/3)

Absolute sum of 2/3 and 16/3 is -2/3+16/3=6

Both numbers are negative, so the sum is negative.

Therefore,−2/3−51/3=−6

The subtraction of −2/3−51/3=−6.

Page 2 Problem 12 Answer

Given: Expression is z−3.5 and z=1.

To subtract the given expression.

First substitute the value of z in the given expression then write it in the form of addition.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

On substituting the value of z and writing it in the form of addition we get -1+(−3.5)

Absolute difference of 1 and 3.5 is -3.5−1=2.5

Using the sign of a number with greater value we get-z−3.5 for z=1 is −2.5

The subtraction of z−35 for z=1 is −2.5.

Page 2 Problem 13 Answer

Given: The record high temperature for Asheville, North Carolina was 99∘F and the record low was −17∘F.

To find The difference between these two temperatures.

Subtract the two temperatures.

Then, write it in the form of addition.

When the signs of the numbers are the same, find the sum of their absolute values.

Both numbers are positive, so the sum is positive.

On subtracting the two temperature and writing it in the form of addition we get -99−(−17)=99+17

Absolute sum of 99 and 17 is -99+17=116

Both numbers are positive, so the sum is positive.

Therefore, 99−(−17)=116

The difference between the two temperatures is 116∘F.

Page 2 Problem 14 Answer

Given: The balance in Mr. Sanchez′s bank account was $293.74 and he accidentally wrote a check for $300.

To find His balance now.

Subtract the check  Mr. Sanchez  accidentaly wrote from his balance bank account.

When the amount that is subtracted is greater than the amount from which it is subtracted, then you can subtract the smaller amount from the larger amount and put the negative sign in the result.

Mr. Sanchez’s bank account balance is $293.74.

He wrote a check of $300.

The new balance will be the difference of the starting balance minus the amount of the chek:

So, his new balance is: 293.74−300=−6.96.

Therefore, the balance amount in Mr. Sanchez’s bank account after the accicentally wrote a check for $300

when the balance of his bank account was $293.74 is −$6.26.

Page 2 Problem 15 Answer

Given: Expression is 18−n and n=−13.

To evaluate the given expression for each value of n.

Substitute the value of n in the given expression and write it in the form of addition.

When the signs of the numbers are the same, find the sum of their absolute values.

Both numbers are positive, so the sum is positive.

On substitute the value of n in the given expression and writing it in the form of addition we get −18−(−13)=18+13

Absolute sum of 18 and 13 is -18+13=31

Both numbers are positive, so the sum is positive.

Therefore, the value of the expression 18−n for n=−13 is 31.

The value of the expression 18−n for n=−13 is 31.

Page 2 Problem 16 Answer

Given: Expression is 18−n and n=8.55.

To evaluate the given expression for each value of n.

Substitute the value of n in the given expression and write it in the form of addition.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

On substitute the value of n in the given expression and writing it in the form of addition we get -18−8.55=18+(−8.55)

Absolute difference of 18 and 8.55 is -18−8.55=9.45

Using the sign of a number with greater value we get-The value of the expression 18−n for n=8.55 is 9.45.

The value of the expression 18−n for n=8.55 is 9.45.

Page 2 Problem 17 Answer

Given: Expression is 18−n and n=201/5.

To evaluate the given expression for each value of n.

Substitute the value of n in the given expression and write it in the form of addition.

When the signs of the numbers are the different, find the difference of their absolute values.

Use the sign of the number with the greater absolute value.

On substitute the value of n in the given expression and writing it in the form of addition we get −18−201/5=18+(−101/5)

Absolute difference of 18 and 101/5 is -101/5−18=11/5

Using the sign of a number with greater value we get-The value of the expression 18−n for n=201/5 is −11/5.

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