Holt Algebra 1 Homework and Practice Workbook 1st Edition Chapter 2
Page 9 Problem 1 Answer
Given: g−7=14
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
g−7=15
Add 7 on both the sides of the equation,
g−7+7=15+7
g=22
After solving the given expression, the value of g is 22.
Page 9 Problem 2 Answer
Given: t+4=6
To Solve each equation.
To solve the given expression, we will subtract the same thing on both the sides.
t+4=6
Subtract 4 from both the sides,
t+4−4=6−4
t=2
After solving the given expression, the value of t is 2.
Page 9 Problem 3 Answer
Given: 13=m−7
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
13=m−7
Add 7 on both the sides,
13+7=m−7+7
20=m
After solving the given expression, the value of m is 20.
Page 9 Problem 4 Answer
Given: x+3.4=9.1
To Solve each equation.
To solve the given expression, we will subtract the same thing on both the sides.
x+3.4=9.1
Subtract 3.4 from both the sides,
x+3.4−3.4=9.1−3.4
x=5.7
After solving the given expression, the value of x is 5.7.
Page 9 Problem 5 Answer
Given: n−3/8=1/8
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
Given: n−3/8=1/8
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
Simplify,
n−3/8+3/8=1/8+3/8
n=4/8
On simplifying 4/8 we get, 1/2.
The value of n is 1/2.
Page 9 Problem 6 Answer
Given: p−1/3=2/3
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
p−1/3=2/3
Add 1/3 on both the sides,
p−1/3+1/3=2/3+1/3
Simplify,
p−1/3+1/3=2/3+1/3
p=3/3
On simplifying 3/3 we get 1.
The value of p is 1.
Page 9 Problem 7 Answer
Given: −6+k=32
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
−6+k=32
Add 6 on both the sides.
−6+k=32
−6+6+k=32+6
k=38
The value of k is 38.
Page 9 Problem 8 Answer
Given: 7=w+9.3
To Solve each equation.
To solve the given expression, we will subtract the same thing on both the sides.
7=w+9.3
Subtract 9.3 from both the sides,
7−9.3=w+9.3−9.3
−2.3=w
The value of w is −2.3.
Page 9 Problem 9 Answer
Given: y−57=−40
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
y−57=−40
Add 57 on both the sides,
y−57+57=−40+57
y=17
The value of y is 17.
Page 9 Problem 10 Answer
Given: −5.1+b=−7.1
To Solve each equation.
To solve the given expression, we will add the same thing on both the sides.
−5.1+b=−7.1
Add 5.1 on both the sides,
−5.1+5.1+b=−7.1+5.1
b=−2
The value of b is −2.
Page 9 Problem 11 Answer
Given: a+15=15
To Solve each equation.
To solve the given expression, we will subtract the same thing on both the sides.
a+15=15
Subtract 15 from both the sides,
a+15−15=15−15
a=0
The value of a is 0.
Page 9 Problem 12 Answer
To write and solve an equation to determine Marietta’s hourly wage before her raise.
Show that your answer is reasonable.
Assume hourly wage and solve the resulting equation.
Let x be her hourly wage before her raise. She was given a raise of $0.75 an hour, which bought her hourly wage to $12.25.
So, the equation, which represents this situation, will be x+0.75=12.25.
Solve for x to get
x=12.25−0.75
x =11.5
So, her hourly wage before the raise was $11.5.
So, her hourly wage before the raise was $11.5.Check if this is true or if you answer is reasonable, by plugging x=11.5 back in the said equation 11.5+0.75=12.25.
Page 9 Problem 13 Answer
Given: Brad grew 41/4 inches this year and is now 567/8 inches tall.
To find Brad’s height at the start of the year.
Show that your answer is reasonable.
We will convert both the given mixed fractions into improper fractions and then we will subtract the value of height grown from the total height to get Brad’s height at the start of the year.
Brad grew 41/4 inches this year. We will convert the mixed fraction to an improper fraction.
We will multiply the denominator of the fraction with the whole number and add whatever there is in the numerator, it can now be written as,
41/4=(4×4)+1/4
On simplifying, we get: 41/4=17/4
Therefore, Brad grew 17/4 inches this year.
Currently Brad is 567/8 inches tall. We will convert the mixed fraction to an improper fraction.
We will multiply the denominator of the fraction with the whole number and add whatever there is in the numerator, it can now be written as,
567/8=(56×8)+7/8
On simplifying, we get:567/8=455/8
Therefore, Brad is 455/8 tall.
Now brads height at the start of the year will be the subtraction of the current height and the height grown.
It can be written as,
⇒455/8−17/4
On taking the lowest common multiple in the denominator, we get,
⇒455/8−34/8
On taking the denominator common, we get,
⇒455−34/8
On simplifying the terms in the numerator, we get,
⇒421/8
Brad’s height at the start of the year is 421/8.
To show the answer reasonable add Brad’s height at the start of the year in his grown height i.e.,
421/8+17/4=421+34/8
421+34/8=455/8
From Step 2 we can write 455/8 as 567/8 which is the current height of Brad’s.
Page 9 Problem 14 Answer
To solve an equation to find Heather’s practice time.
Heather’s finishing time is 2.6 seconds less than her practice time, so ,
Finishing time=Practice time−2.6 seconds.
Let P= practice time.
58.4=P−2.6
Add 2.6 to both sides,61=P.
Heather’s practice time is 61 seconds.
Page 9 Problem 15 Answer
Given: Radius of Earth 6378.1 km
To determine the radius of Mars.
Let the radius of Mars be R
As it is given that the radius of Earth is 2981.1 Km bigger than the radius of Mars,
So,6378.1km=R+(2981.1km)
Subtract (2981.1 km) from both sides of the equation.
6378.1−2981.1=R+2981.1−2981.1
3397=R
The Radius of Mars is 3397Km.
To show the answer reasonable add the radius of Mars in 2981.1 we will get the Radius of earth.