Holt Algebra 1 Homework and Practice Workbook 1st Edition Chapter 2
Page 10 Problem 1 Answer
Given,d/8=6
To find : the value of d.
Solve the above equation and find the value of d.
Consider the given equation.
d/8=6
Cross multiplying, we get
d=8×6
d=48
Now, check our answer
48/8=6
6=6
Hence, the value of d is 48.
Page 10 Problem 2 Answer
Given,−5=n/2
To find : the value of n.
Solve the above equation and find the value of n.
Consider the given equation.
−5=n/2
Cross multiplying, we get
−5×2=n
n=−10
Now, check our answer
−5=−10/2
−5=−5
Hence, the value of n is −10.
Page 10 Problem 3 Answer
Given,−t/2=12
To find : the value of t.
Solve the above equation and find the value of t.
Consider the given equation.
−t/2=12
On solving the above equation, we get
−t=2×12
−t=24
t=−24
Now, check my answer
−(−24)/2=12/24
2=12
12=12
Hence, the value of t is −24.
Page 10 Problem 4 Answer
Given,−40=−4x
To find : the value of x
Solve the above equation and find the value of x.
Consider the given equation.
−40=−4x
On dividing the above equation by −4, we get
−40−4=−4x
−4/10=x
x=10
Now, check my answer
−40=−4(10)
−40=−40
Hence, the value of x is 10.
Page 10 Problem 5 Answer
Given,2r/3=16
To find : the value of r
Solve the above equation and find the value of r.
Consider the given equation.
2r/3=16
On solving the above equation, we get
2r=3×16
2r=48
r=48/2
r=24
Now, check my answer
2(24)/3=16/48
3=16
16=16
Hence, the value of r is 24.
Page 10 Problem 6 Answer
Given,−49=7y
To find : the value of y
Solve the above equation and find the value of y.
Consider the given equation.
−49=7y
On dividing the above equation by 7, we get
−49/7=7y
7−7=y
y=−7
Now, check our answer
−49=7(−7)
−49=−49
Hence, the value of y is −7.
Page 10 Problem 7 Answer
Given,−15=−3n/5
To find : the value of n.
Solve the above equation and find the value of n.
Consider the given equation.
−15=−3n/5
On solving the above equation, we get
−15×5=−3n
−3n=−75
n=−75/−3
n=25
Now, check our answer
−15=−3(25)/5
−15=−15
Hence, the value of n is 25.
Page 10 Problem 8 Answer
Given,v−3=−6
To find : the value of v.
Solve the above equation and find the value of v.
Consider the given equation.
v−3=−6
On solving the above equation, we get
v=−6×−3
v=18
Now, check my answer
18−3=−6
−6=−6
Hence, the value of v is 18.
Page 10 Problem 9 Answer
Given,
2.8=b/4
To find: the value of b
Solve the above equation and find the value of b.
Consider the given equation.
2.8=b/4
Cross multiplying, we get
b=2.8×4
b=11.2
Now, check our answer
2.8=11.2/4
2.8=2.8
Hence, the value of b is 11.2.
Page 10 Problem 10 Answer
Given, 3r /4=1/8
To find: the value of r
Solve the above equation and find the value of r.
Consider the given equation.
3r/4=1/8
On solving the above equation, we get
3r=4/8
3r=1/2
r=1/6
Now, check my answer
3(1/6)/4=1/8
1/2/4=1/8
1/8=1/8
Hence, the value of r is 1/6.
Page 10 Problem 11 Answer
Given, The price of the package = $2.07
The first-class rate at the time = $0.23 per ounce
To find the weight of the package.
Apply the concept of linear equation. And solve the equation.
Given, The price of the package =$2.07
The first-class rate at the time =$0.23 per ounce
Let ′x′ be the weight of the package.
According to the question,
0.23x=2.07
x=2.07/0.23
x=9
Hence, the weight of the package is 9 ounce.
Page 10 Problem 12 Answer
Given, Lola spends $8 per at the movies.
To find : Lola’s weekly allowance.
Apply the concept of linear equation.
And solve the equation.
Given, Lola spends $8 per at the movies.
Let ′x′ be Lola’s weekly allowance.
According to the given question,
1/3
x=8
x=8×3
x=24
Hence, Lola’s weekly allowance is $24.