Holt Algebra 1 Homework and Practice Workbook 1st Edition Chapter 2 Exercise 2.6

Holt Algebra 1 Homework and Practice Workbook 1st Edition Chapter 2

Page 14 Problem 1 Answer

Given: The ratio of freshman to sophomores in a drama club is 5: 6. There are 18 sophomores in the drama club.

To Find: How many freshmen are there?

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

The ratio of freshman to sophomores in a drama club is Freshman/Sophomores=5/6.

There are 18 sophomores in the drama club.

Freshman/Sophomores=5/6 Freshman

18=5/6

⇒Freshman=5/6×18

⇒Freshman=15

​Number of freshman=15

Page 14 Problem 2 Answer

Given:  Four pounds of apples cost1.96

To Find: unit rate

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

As we have four pounds of apples cost 196

Cost of 4 apples=1.96

Cost of 1 apples=1.96/4

Cost of 1 apple=0.49

​Therefore, cost of 1 apple=0.49 dollars

Page 14 Problem 3 Answer

Given: Sal washed 5 cars in 50 minutes

To Find: unit rate

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

According to the question we have

Minutes for washing 5 cars=50

Minutes for washing 1 car=50/5

Minutes for washing 1 car=10​

Therefore, unit is 10 minutes per car

Page 14 Problem 4 Answer

Given: A giraffe can run 32 miles per hour.

To Find: What is this speed in feet per second?

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

According to question a giraffe can run 32 miles per hour.

Using 1 mile =5280 feet and 1 hour =60×60 second

we get Then a giraffe can run

32×miles hour

=32×5280

60×60×feet second

=47 feet per seond

​32×miles per hour =47 feet per seond

Page 14 Problem 5 Answer

Given: proportion is y/4=10/8

To Find: value of variable

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

Cross multiplying the given proportion

Y/4=10/8

⇒8y=10×4

⇒y=10×4/8

⇒y=5

​Required value is y=5

Page 14 Problem 6 Answer

Given: proportion is 2/x=30−6

To Find: value of variable

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

Cross multiplying the given proportion

2/x=30−6

⇒−12=30×x

⇒x=−12/30

⇒x=−2/5

⇒x=−1/2.5

⇒x=−0.4

​Required value is x=−0.4

Page 14 Problem 7 Answer

Given: proportion is 3/12=−24/m

To Find: value of variable

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

Cross multiplying the given proportion

3/12=−24m

⇒1/4 =−24m

⇒m=−24×4

⇒m=−96

​Required value ism=−96

Page 14 Problem 8 Answer

Given: proportion is 3t

10=1/2

To Find: value of variable

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

Cross multiplying the given proportion

3t/10=1/2

⇒3t×2=10

⇒t=10/6

⇒t=1.67

​Required value is t=1.67

Page 14 Problem 9 Answer

Given: proportion is 7x=1/0.5

To Find: value of variable

Method Used: Simplification using addition, subtraction, division or multiplication of integers.

Cross multiplying the given proportion

7/x=1/0.5

⇒7×0.5=x

⇒x=3.5

​Required value is x=3.5

Page 14 Problem 10 Answer

Given: The scale of his model to the actual car is 1:10

and his model is 181/2 inches long

To Find: How long is the actual car?

Method Used: use of formula of scale

Here, 1 inch model/10 inches actual=18.5 inch model/x inches actual

x=18.5×10/1

=185 inches

​Actual length is=185 inches

Page 14 Problem 11 Answer

Given: The scale on a map of Virginia shows that 1 centimeter represents 30 miles.

The actual distance from Richmond, VA to Washington, DC is 110 miles.

To Find: how many centimeters are between the two cities?

Method Used: use of formula of scale.

Scale is given as dimension on map actual dimension

Here, 1 centimeters represents 30 miles then

30 miles =1 cm

1 mile =1/30cm

110 miles =1/30×110

110 miles =3.67 cm

​Required distance in map is110 miles =3.67 cm

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