Primary Mathematics Chapter 2 The Four Operations Of Whole Numbers
Chapter 2 The Four Operations Of Whole Numbers Exercise 2.1 Solutions Page 40 Exercise 2.1 Problem 1
To find – The sum of
7 4 2 3
+ 6 5 2
_________
Place the digits under respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place values
7 4 2 3
+ 6 5 2
___________
Adding the digits in each place value
Th H T O
7 4 2 3
+ 6 5 2
___________
8 0 7 5
Hence, the sum of ⇒ 7 4 2 3 + 6 5 2 = 8075.
Page 40 Exercise 2.1 Problem 2
To find – The sum of
2 3 5 7
+ 6 5 2
__________
Place the digits under respective place values.
Add the digits in each place value taking the carryover, if any, to the next column to the left, and add it along with the digit in that place value.
Continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place values,
Th H T O
2 3 5 7
+ 6 5 2
___________
Adding the digits in each place value
Th H T O
2 3 5 7
+ 6 5 2
_____________
3 0 0 9
Hence, the sum of ⇒ 2 3 5 7 + 6 5 2 = 3009.
Primary Mathematics 4A Chapter 2 Step-By-Step Solutions For Exercise 2.1 Page 41 Exercise 2.1 Problem 3
Given: Some numbers.
To find – The difference between the given numbers.
The difference between two numbers is nothing but the subtraction of the smallest number from the largest number.
Follow the steps given below.
Complete the subtractions in the first row.
The first difference (subtraction) is given by
5 6 7 8
1 2 3 4
−
____________
4 4 4 4
The second difference (subtraction) is given by
8 4 3 2
− 9 7 6
_________
7 4 5 6
The third difference (subtraction) is given by
5 1 2 3
1 2 3 4
−
_________
3 8 8 9
Complete the subtractions in the second row.
The first difference (subtraction) is given by
3 0 0 0
2 8 7 4
−
__________
1 2 6
The second difference (subtraction) is given by
9 0 0 1
− 1 2 8
__________
8 8 7 3
The third difference (subtraction) is given by
6 0 6 0
3 6 8 7
−
__________
2 3 7 3
Complete the subtractions in the third row.
The first difference (subtraction) is given by
5 2 6 2
4 9 0 8
−
__________
3 5 4
The second difference (subtraction) is given by
1 0 0 6
− 8 9 7
___________
1 0 9
The third difference (subtraction) is given by
9 0 2 2
1 1 3 4
−
__________
7 8 8 8
Complete the subtractions in the fourth row.
The first difference (subtraction) is given by
4 2 0 0
1 5 3 2
−
_________
2 6 6 8
The second difference (subtraction) is given by
1 9 8 2
− 9 9 9
_________
9 8 3
The third difference (subtraction) is given by
7 2 5 8
6 1 8 9
_
__________
1 0 6 9
The complete difference for each expression is given below.
The Four Operations Exercise 2.1 Primary Mathematics Workbook Answers Page 41 Exercise 2.1 Problem 4
Given: Some numbers in a box.
To find – The name of the city which is a landmark of Golden Bridge.
Referring to Exercise 2.1 above table it is obtained that
Observe that, the first given number 109 corresponds to the letter “S” in the above table.
The second given number 1069 corresponds to the letter “A “ in the above table.
The third given number 3889 corresponds to the letter “N “ in the above table, and so on…
Finally, in this way, all the letters will form the word “SAN FRANCISCO” as shown in the table below.
The city that is the landmark of Golden Bridge is “SAN FRANCISCO” which is represented by the following table.
Common Core Primary Mathematics 4A Chapter 2 Solved Examples For 2.1 Page 42 Exercise 2.2 Problem 1
To find – The sum of
⇒ 8 + 2
⇒ 28 + 2
⇒ 328 + 2
⇒ 6,328 + 2
Place the digits under respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place values for each sum
Adding the digits in each place value
Hence, the addition is ⇒ 8 + 2 = 10 28 + 2 = 30 328 + 2 = 330, and 6,328 + 2 = 6330.
Solutions For The Four Operations Exercise 2.1 In Primary Mathematics 4A Page 42 Exercise 2.2 Problem 2
To find – The sum of
⇒ 4 + 6
⇒ 54 + 6
⇒ 254 + 6
⇒ 3,254 + 6
Place the digits under respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place values for each sum
Adding the digits in each place value,
Hence, the addition is ⇒ 4 + 6 = 10 , 54 + 6 = 60, 254 + 6 = 260, and 3,254 + 6 = 3260.
Detailed Solutions For Exercise 2.1 The Four Operations In 4A Workbook Page 42 Exercise 2.2 Problem 3
To find – The sum of 2,457 + 4
Place the digits under the respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place values for each sum
Th H T O
2 4 5 7
+ 4
____________
Adding the digits in each place value
Th H T O
2 4 5 7
+ 4
_________
2 4 6 1
Hence, the addition is ⇒ 2,457 + 4 = 2461.
Page 42 Exercise 2.2 Problem 4
Given: 2,839 + 6
We have to find the sum of these numbers.
Place the digits under respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place value for each sum
Th H T O
2 8 3 9
+ 6
___________
Adding the digits in each place value and taking carry over
Th H T O
2 8 3 9
+ 6
____________
2 8 4 5
Hence, the addition will be ⇒ 2,839 + 6 = 2845.
Step-By-Step Guide For The Four Operations Exercise 2.1 In 4A Workbook Page 43 Exercise 2.2 Problem 5
To subtract
⇒ 10 − 6
⇒ 40 − 6
⇒ 250 − 6
⇒ 5,230 − 6
Place the digits under respective place values.
Beginning with the ones, we go on subtracting place value wise borrowing if necessary, from the next place value to the left.
Referring to the question and placing digits under respective place value for each sum
TO TO HTO ThHTO
10 40 250 5230
−6 −6 −6 −6
_________________________
Subtracting the digits in each place value
TO TO HTO ThHTO
10 40 250 5230
−6 −6 −6 −6
______________________
4 34 244 5224
Hence, the result of subtraction is ⇒ 10 − 6 = 4, 40 − 6 = 34, 250 − 6 = 244, and 5,230 − 6 = 5224.
Page 43 Exercise 2.2 Problem 6
To subtract
⇒ 10 − 9
⇒ 100 − 9
⇒ 1,000 − 9
⇒ 2,000 − 9
Place the digits under respective place values.
Beginning with the ones, we go on subtracting place value wise, borrowing if necessary, from the next place value to the left.
Referring to the question and placing digits under respective place value for each sum
TO HTO ThHTO ThHTO
10 100 1000 2000
−9 −9 −9 −9
_____________________________
Subtracting the digits in each place value
TO HTO ThHTO ThHTO
10 100 1000 2000
−9 −9 −9 −9
______________________________
1 91 991 1991
Hence, the result of subtraction is ⇒ 10 − 9 = 1, 100 − 9 = 91, 1,000 − 9 = 991 and, 2,000 − 9 = 1991.
Primary Mathematics Workbook 4A Exercise 2.1 The Four Operations Page 43 Exercise 2.2 Problem 7
To subtract – 2,570 − 68.
Place the digits under respective place value.
Beginning with the ones, we go on subtracting place value wise, borrowing if necessary, from the next place value to the left.
Referring to the question and placing digits under respective place value for each sum
Th H T O
2 5 7 0
−6 8
___________
Subtracting the digits in each place value
Th H T O
2 5 7 0
−6 8
_______________
2 5 0 2
Hence, the result of subtraction is 2,570 − 68 = 2,502.
Chapter 2 The Four Operations Exercise 2.1 Breakdown With Solutions Page 43 Exercise 2.2 Problem 8
To subtract – 3,410 − 9.
Place the digits under respective place value.
Beginning with the ones, we go on subtracting place value wise, borrowing if necessary, from the next place value to the left.
Referring to the question and placing digits under respective place value for each sum
Th H T O
3 4 1 0
−9
____________
Subtracting the digits in each place value
Th H T O
3 4 1 0
−9
____________
3 4 0 1
Hence, the result of subtraction is 3,410 − 9 = 3,401.
Common Core 4A Chapter 2 Exercise 2.1 Solutions Page 44 Exercise 2.3 Problem 1
To add
⇒ 1,582 + 9
⇒ 1,582 + 99
⇒ 1,582+999
Place the digits under respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place value for each sum
Subtracting the digits in each place value
Hence, the result of addition is ⇒ 1,582 + 9 =1,591, 1,582 + 99 = 1,681 and 1,582 + 999 = 2,581.
Page 44 Exercise 2.3 Problem 2
To add
⇒ 2,756+8
⇒ 2,756+98
⇒ 2,756+998
Place the digits under respective place values.
Add the digits in each place value, and continue this process till we add the digits in all the place values.
Referring to the question and placing digits under respective place value for each sum
Subtracting the digits in each place value
Hence, the result of addition is ⇒ 2,756 + 8 = 2,764, 2,756 + 98 = 2,854 and 2,756 + 998 = 3,754.
Page 44 Exercise 2.3 Problem 3
Given: 1963 + 98
To find: Add or subtract. By using mathematical operation we can add it or solve it.
First, we perform operation that is given
Adding 1963 and 98 ⇒ 1963 + 98 = 2061
Addition is 1963 + 98 = 2061
Page 44 Exercise 2.3 Problem 4
Given: 7981 − 99
To find – Subtract.By using given operation we can solve it.
Subtracting 99 into 7981 ⇒ 7981 − 99 = 7882
Subtraction is 7981 − 99 = 7882
Page 44 Exercise 2.3 Problem 5
Given: 9405 − 998
To find – Subtract
We can write, 9405 − 998 = 8407 (Subtracting)
Subtraction is 9405− 998 = 8407
Page 44 Exercise 2.3 Problem 6
Given: 3824+997
To find – Find addition.
By using mathematical operation, we can write
3824 + 997 = 4821 (Adding 3824 and 997)
Addition is 3824 + 997 = 4821
Page 44 Exercise 2.3 Problem 7
Given: 6448 + 199
To find – Solve addition.
First, we write, 6448 + 199 = 6647 (Adding 6448 and 199, and simplify)
The addition is 6448 + 199 = 6647
Page 44 Exercise 2.3 Problem 8
Given: 5832 − 598
To find – Subtract the given number.
By using mathematical operation we can solve it.
5832−598 = 5234 (Subtracting 598 from 5832, and simplify)
Subtraction is 5832−598 = 5234
Page 45 Exercise 2.3 Problem 9
Given: 2100 − 80
To find – Subtract.
By using mathematical operation we can solve it.
2100 − 80 = 2020 (Subtracting 80from 2100, and simplify)
Subtraction is 2100 − 80 = 2020
Page 45 Exercise 2.3 Problem 10
Given: 2700 − 98
To find – Subtract 2700 and 98
By using mathematical operation we can solve it.
2700 − 98 = 2602 (Subtracting 98from 2700, and simplify)
Subtraction is 2700 − 98 = 2602
Page 45 Exercise 2.3 Problem 11
Given: 3200 − 54
To find – Subtract the given numbers.
By using mathematical operation we can solve it.
3200−54 = 3146 (Subtracting 54 from 3200, and simplify)
Subtraction is 3200 − 54 = 3146
Page 45 Exercise 2.3 Problem 12
Given: 3900−99
To find – SubtractBy using mathematical operation
3900 − 99 = 3801 (Subtracting 99 from 3900, and simplify)
Subtraction is 3900 − 99 = 3801
Page 45 Exercise 2.3 Problem 13
Given: 4200 − 98
To find – SubtractWe have
4200 − 98 = 4102 (Subtracting 98 from 4200, and simplify)
Subtraction is 4200 − 98 = 4102
Page 45 Exercise 2.3 Problem 14
Given: 3000 − 400
To find – Subtract 400 from 3000
First, we can write
3000−400=2600(Subtracting and simplify)
Subtraction is 3000 − 400 = 2600
Page 45 Exercise 2.3 Problem 15
Given: 3000 − 750
To find – Subtract
We can solve it by using the operation,
3000 − 750 = 2250 (Subtracting 750 from 3000 and simplify)
Subtraction is 3000 − 750 = 2250
Page 45 Exercise 2.3 Problem 16
Given: 3000−530
To find – Subtract
By using mathematical operation we can solve it
3000−530 = 2470 (Subtracting 530from 3000, and simplify)
Subtraction is 3000−530 = 2470
Page 45 Exercise 2.3 Problem 17
Given: 3000−999
To find – Subtract
We have, 3000−999 = 2001 (Subtracting 999 from 3000 , and simplify)
Subtraction is 3000 − 999 = 2001
Page 45 Exercise 2.3 Problem 18
Given: 4000−998
To find – Subtract
We have, 4000 − 998 = 3002 (Subtracting 998 from 4000 , and simplify)
Subtraction is 4000 − 998 = 3002
Page 46 Exercise 2.4 Problem 1
Given: 3890+14
To find – Add 3890 and 14
By using mathematical operation (addition) we can solve it.
We have
3890+14 = 3904 (Add 3890 and 14, and simplify)
Addition is 3890+14 = 3904
Page 46 Exercise 2.4 Problem 2
Given: 3598+42
To find – Add 3598 and 42
By solving mathematical operation we can solve it
3598 + 42 = 3640 (Add 3598 and 42, and simplify)
Addition is 3598 + 42 = 3640
Page 46 Exercise 2.4 Problem 3
Given: 4264 + 38
To find – Add 4264 and 38
We first write given operation and then solve
4264 + 38 = 4302 (Add 4264 and 38, and simplify)
Addition is 4264 + 38 = 4302
Page 46 Exercise 2.4 Problem 4
Given: 2700 + 324
To find – Add 2700 + 324
By using addition we can solve it
2700 + 324 = 3024 (Add 2700 and 324, and simplify)
Addition is 2700 + 324 = 3024
Page 46 Exercise 2.4 Problem 5
Given: 2997+203
To find – Add 2997+203
By using addition we can solve it
2997 + 203 = 3200 (Add 2997 and 203, and simplify)
Addition is 2997 + 203 = 3200
Page 46 Exercise 2.4 Problem 6
Given: 2998 + 275
To find – Add 2998 and 275
By using addition we can solve it
2998 + 275 = 3273 (Add 2998 and 275, and simplify)
Addition is 2998275 = 3273
Page 47 Exercise 2.4 Problem 7
Given: 2543 + 68 =_____
To find – Write the missing numbers.
By using mathematical operations we can solve it
2543 + 60 = 2603
2603 + 8 = 2611
First, we add +60 into 2543 and then we add +8 into 2603
Answer is ⇒ 2543+ 60 = 2603, 2603 + 8 = 2611, 2543 + 68 = 2611
Page 47 Exercise 2.4 Problem 8
Given: 3276 + 2040 = _______
To find – Write the missing numbers.
First, we add 2000 and then we add 40 into 5276
3276 + 2000 = 5276
5276 + 40 = 5316
3276 + 2040 = 5316
Missing numbers are ⇒ 3276 + 2000 = 5276, 5276 + 40 = 5316, 3276 + 2040 = 5316
Page 47 Exercise 2.4 Problem 9
Given: 3524 − 630 = ______
To find – Write the missing number.
By using mathematical operations we can solve.
First, we subtract 600 and then subtract 30 from 3524
3524−600 = 2924
2924−30 = 2894
3524−630 = 2894
Missing numbers are ⇒ 3524 − 600 = 2924, 2924 − 30 = 2894, 3524 − 630 = 2894
Page 47 Exercise 2.4 Problem 10
Given: 4261−2500=?
To find – Write missing numbers.
By using mathematical operations we can solve it.
\(4261 \stackrel{-2000}{\longrightarrow} 2261 \stackrel{-500}{\longrightarrow} 1761\)
4261- 2500 = 1761
The missing numbers are ⇒ \(4261 \stackrel{-2000}{\longrightarrow} 2261 \stackrel{-500}{\longrightarrow} 1761\), \(4261-2500\)= 1761
Page 47 Exercise 2.4 Problem 11
Given: 3423 − 607
To find – Subtract 607 from 3423
Subtracting 607 from 3423 we get, 3423−607 = 2816
The subtraction is 2816.
Page 47 Exercise 2.4 Problem 12
Given: 5697 − 2700
To find – Subtract 2700 from 5697
Subtracting 2700 from 5697 we get, 5697−2700=2997
Subtraction is 2997.
Page 48 Exercise 2.5 Problem 1
Given: 319 + 589
To find – Round each number to the nearest hundred then estimate it.
First, we round each number to the nearest hundred then we solve it.
319 + 589
↓
300 + 600 = 900
The estimate value of expression is 900.
Page 48 Exercise 2.5 Problem 2
Given: 782 − 509
To find – Round the number to nearest hundred then estimate it.
First, we write round the number to nearest hundred then solve it.
780 − 509
↓ ↓
800 − 500 = 300
The estimate value of expression is 300.
Page 48 Exercise 2.5 Problem 3
Given: 792 + 204
To find – Round the number to nearest hundred then estimate expression.
First, we round the number to nearest hundred then solve.
792 + 204
↓ ↓
800 + 200 = 1000
The estimate value of expression is 1000.
Page 48 Exercise 2.5 Problem 4
Given: 903 − 288
To find – Round the number to nearest hundred then estimate expression.
First, we round the number to nearest hundred then solve.
903 − 288
↓ ↓
900 − 300 = 600
The estimate value of expression is 600.
Page 48 Exercise 2.5 Problem 5
Given: 612 + 589
To find – Round the number to nearest hundred then estimate expression.
First, we round the number to nearest hundred then solve.
612 + 589
↓ ↓
600 + 600 = 1200
The estimate value of expression is 1200.
Page 48 Exercise 2.5 Problem 6
Given: 892−328
To find – Round the number to nearest hundred then estimate expression.
First, we round the number to nearest hundred then estimate expression.
892 − 328
↓ ↓
900 − 300 = 600
The estimate value of expression is 600.
Page 48 Exercise 2.5 Problem 7
Given: 1798 + 416
To find – Round the number to nearest hundred then estimate it.
First, we round the number to nearest hundred then solve.
1798 + 416
↓ ↓
1800 + 400 = 2200
The estimate value of expression is 2200.
Page 48 Exercise 2.5 Problem 8
Given: 2304−996
To find – Round the number to nearest hundred then estimate value of expression.
First, we round the number to nearest hundred then solve.
2304 − 996
↓ ↓
2300 − 1000 = 1300
The estimate value of expression is 1300.
Page 49 Exercise 2.5 Problem 9
Given: 296 + 109 + 394
To find – Round the number to nearest hundred then solve.
First, we round the number to nearest hundred then solve it.
296 + 109 + 394
↓ ↓ ↓
300 + 100 + 400 = 800
The estimate value of expression is 800.
Page 49 Exercise 2.5 Problem 10
Given: 704 − 196 − 312
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
704 − 196 − 312
↓ ↓ ↓
700 − 200 − 300 = 200
The estimate value of expression is 200.
Page 49 Exercise 2.5 Problem 11
Given: 998 − 194 + 97
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
998 − 194 + 97
↓ ↓ ↓
1000 − 200 + 100 = 900
The estimate value of expression is 900.
Page 49 Exercise 2.5 Problem 12
Given: 499 + 301 − 29
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
499 + 301 − 29
↓ ↓ ↓
500 + 300 − 30 = 770
The estimate value of expression is 770.
Page 49 Exercise 2.5 Problem 13
Given: 1992 − 67 + 489
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
2000 − 70 + 500 = 2430
The estimate value of expression is 2430.
Page 49 Exercise 2.5 Problem 14
Given: 2409 + 593 − 708
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
2400 + 600 − 700 = 2300
The estimate value of expression is 2300.
Page 49 Exercise 2.5 Problem 15
Given: 1109 − 98 + 392
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
1100 − 100 + 400 = 1410
The estimate value of expression is 1410.
Page 49 Exercise 2.5 Problem 16
Given: 3012 + 62 + 402
To find – Round the number to nearest hundred then solve it.
First, we round the number to nearest hundred then solve it.
3010 + 70 + 400 = 3480
The estimate value of expression is 3480.
Page 50 Exercise 2.6 Problem 1
Given: 4670
European stamps and 698 African stamps more than European stamps.
To find – Total stamps altogether.
First, we write given stamps and then we add all stamps.
European − Stamps → African − stamps → Total−stamps
4670 + 4670 + 698 =
4670 + 5368 = 10038
Sarah have 10038 total stamps.
Page 50 Exercise 2.6 Problem 2
Given: I Drove 325 miles on Saturday.
To find – How many miles did she travels on two days?
First, we add 49 miles to 325 miles for Sunday drove then we calculate for both days drove.
325miles + 49miles = 374miles on Sunday.
For two days travel is:
325miles + 374miles = 699miles
Mrs. Charles did travels on both days are 699 miles.
Page 51 Exercise 2.6 Problem 3
Given: Cost $3225 for Piano.
To find – How much more money does she need?
First, we add total money then we subtract total money from the Piano cost.
Total money, $1950 + $625 = $2575
Now she needs money more
$3225 − $2575 = $650
Mrs. Gina need $650 more money.
Page 51 Exercise 2.6 Problem 4
Given: Earned $2365 in January, $2740 in February.
To find – How much did he saved?
First, we calculate both months earned money then we subtract spend money from earned money.
Earned in January = $2365
Earned in February ($2365+$375) = $2740
Total = $2365 + $2740
= $5105
He spent $4250, Now we calculate saving $5105 − $4250=$855, Mr. Mudley save $855.
Page 52 Exercise 2.7 Problem 1
We are given to estimate and multiply for 82 × 6.
So, the nearest round figure for 82 is 80.
So, the estimation will be 80 × 6 = 480.
Therefore, the estimated product is 80 × 6 = 480.
Page 52 Exercise 2.7 Problem 2
We are given to estimate and multiply for 79 × 6.
So, the nearest round figure for 79 is 80.
So, the estimation will be 80 × 7 = 560.
Therefore, the estimated product is 80 × 7 = 560.
Page 52 Exercise 2.7 Problem 3
We are given to estimate and multiply for 83 × 8.
So, the nearest round figure for 83 is 80.
So, the estimation will be 80 × 8 = 640.
Therefore, the estimated product is 80 × 8 = 640
Page 52 Exercise 2.7 Problem 4
We are given to estimate and multiply for 96 × 9.
So, the nearest round figure for 96 is 100.
So, the estimation will be 100 × 9 = 900.
Therefore, the estimated product is 100 × 9 = 900.
Page 53 Exercise 2.7 Problem 5
We are given to estimate and multiply for 213 × 5.
So, the nearest round figure for 213 is 200.
So, the estimation will be 200 × 5 = 1000.
Therefore, the estimated product is 200 × 5 = 1000.
Page 53 Exercise 2.7 Problem 6
We are given to estimate and multiply for 497 × 4.
So, the nearest round figure for 497 is 500.
So, the estimation will be 500 × 4 = 2000.
Therefore, the estimated product is 500 × 4 = 2000.
Page 53 Exercise 2.7 Problem 7
We are given to estimate and multiply for 706 × 8.
So, the nearest round figure for 706 is 700.
So, the estimation will be 700 × 8 = 5600.
Therefore, the estimated product is 700 × 8= 5600.
Page 53 Exercise 2.7 Problem 8
We are given to estimate and multiply for 898 × 7.
So, the nearest round figure for 898 is 900.
So, the estimation will be 900 × 7 = 6300.
Therefore, the estimated product is 900 × 7 = 6300.
Page 54 Exercise 2.7 Problem 9
We are given to multiply the given numbers:
By multiplying, we get
⇒ 34 × 4 = 136
⇒ 47 × 5 = 235
⇒ 228 × 3 = 684
⇒ 219 × 6 = 1314
⇒ 357 × 7 = 2499
⇒ 285 × 9 = 2565
⇒ 356 × 8 = 2848
⇒ 489 × 9 = 4401
Therefore, by multiplying the given numbers we get the below answers.
⇒ 34 × 4 = 136
⇒ 47 × 5 = 235
⇒ 228 × 3 = 684
⇒ 219 × 6 = 1314
⇒ 357 × 7 = 2499
⇒ 285 × 9 = 2565
⇒ 356 × 8 = 2848
⇒ 489 × 9 = 4401